A pendulum is 0.850 m long, and the bob has a mass of 1.00 kg. At the bottom of its swing, the bob’s speed is 1.60 m/s. A) What is the tension in the string at the bottom of the swing? in N B)The tension is greater than the weight of the bob because a- its horizontal component is increasing from zero.   b-the bob has a downward acceleration, so the net Fy must be downward.   c- the bob has an upward acceleration, so the net Fy must be upward.   d- the bob has zero acceleration.

A block of mass m on a frictionless surface is attached to a massless spring of constant k, When theblock is at x = 0, the spring is neither stretched nor compressed.At time ti the block is released from rest at x = xi . At time tf theblock passes x = 0 moving to the left with speed vf

Question 1 A11.3 kg block is glued to the top of a vertical spring, with spring constant 680. N/m, compressing it a certain distance. A rope is then tied to the block and pulled upwards with a tension of 680. N. How fast is the block going after it's been pulled upward over a total distance of 1.70 m? (Remember that the block is glued to the spring)

A0.290 kg frame, when suspended from a coil spring, stretches the spring 0.0400 m. A 0.200 kg lump of putty is dropped from rest onto the frame from a height of 30.0 cm (Figure 1). Part A Find the maximum distance the frame moves downward from its initial equilibrium position. Express your answer with the appropriate units. HA ? d = Value Units Figure 30.0 cm

Move over Jeff Bezos, this invention is about to make you the richest person in the world. You have just invented the OyOy (that's YoYo spelled backwards). It is the very latest in home safety and so easy to use!If your building is on fire, simply reach out and grab the cord on the OyOy and you will be lowered safely toward the ground at a low velocity. The OyOy has a total mass M = 94.0 kg and is shaped like a cylinder of radius R = 0.810 meters. The secret to the operation of the OyOy is its patented shaft whose radius is only r = 0.0800 meters. The cord is wound around the small shaft and this is the secret to your low velocity. We will use the approximation that the shaft is of negligible mass compared to the total. This means that you can treat the entire OyOy as though it is a solid cylinder with mass M and radius R. Imagine that a customer of mass m = 85.5 kg is using the OyOy and begins his decent from an initial height of y0 = 11.20 meters.Determine all the following:The…

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A baseball of mass m = 0.56 kg is spun vertically on a massless string of length L = 0.68 m. The string can only support a tension of Tmax = 10.3 N before it will break. a.) What is the maximum possible speed of the ball at the top of the loop, in meters per second? b.) What is the maximum possible speed of the ball at the bottom of the loop, in meters per second?

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2. A 1.0 kg block initially at rest falls vertically and lands on a massless spring. Assume that the block comes to a stop momentarily after it compresses the spring. The block is initially 0.1 m away from the spring and the spring constant k = 1000 N/m. Use g = 9.8 m/s2 as the gravitational acceleration. (a) (b) subsequent state of motion of the block and explain your answer. %3D How much is the spring compressed? What happens after the block comes to a momentary stop? That is, analyze the

A 10 kilogram object suspended from the end of a vertically hanging spring stretches the spring 9.8 centimeters. At time t = 0, the resulting mass-spring system is disturbed from its rest state by the force F(t) = 50 cos(10t). The force F(t) is expressed in Newtons and is positive in the downward direction, and time is measured in seconds. a. Determine the spring constant k. k = 1000 Newtons / meter b. Formulate the initial value problem for y(t), where y(t) is the displacement of the object from its equilibrium rest state, measured positive in the downward direction. (Give your answer in terms of y, y', y", t.) Differential equation: (equations) Initial conditions: y(0) = 0 and y'(0) c. Solve the initial value problem for y(t). y(t) = = 0 help help (numbers) help (formulas) d. Plot the solution and determine the maximum excursion from equilibrium made by the object on the time interval 0 ≤ t < ∞. If there is no such maximum, enter NONE. maximum excursion = meters help (numbers)