Design a most efficient pump size (Find the pump and associated pump curves on the next page) to discharge water through the system shown below. Find the operating system point. Include losses from transitions and fittings. The performance curve Assume f = 0.015. Elev. = 160 m Elev. = 100 m Pump Elbow r/d=2 1000-m pipe; 10 cm dia.

MECHANICS OF FLUIDS (I)

1 QUESTION 1 Consider a desired pump operating condition which adds 35 psi at a flowrate of 500 gpm to water (p= 62 11m/ft²³) Ignore any changes in Kinetic or potential energy and Tassume isothermal flow C.e. internal energy is constant, this is the normal assumption we make when analyzing fluid flows in piping systems). Apply the energy balance only across the pump with full energy Balance and simlifying to solve for the pump, Starting head symbolically. Then begin careful of units, Solve for pump head in feet. GIVEN: 35psi 500 gpm p=62 1bm/3 XA. 10.5 A B. 100.8 ft C. 50.1 ft D. 80.7f 35 500 62 (32.2) + 2(32.2) 35 + 500

02 h, are 12m. The pump efficiency is 79%, and the pump is driven by an electric motor. A pump moves water @10°C from a lake into a large, pressurized holding tank as shown. The flow rate, Q. is 375 L/min, and the piping system losses, 1) Sketch the setup (simple schematic is good), 2) label the z datum, and 3) identify and label the boundary conditions (P, V, and z) at 1 and 2 for use in a) the General Energy Equation (GEE). Provide values and units for the boundary conditions. Hint: For identifying good locations for boundary conditions, where are the velocities approximately zero? b) Calculate the head added to the fluid, h,, by the pump. Give your answer in units of m. Hint: Be careful with signs in manipulating the GEE. Show as many steps as you need to get your h, equation correct. Calculate the power added to the fluid by the pump in units of kW. () Determine the required electric motor size to drive the pump in units of HP. Prank = 200 kPa Holding Tank Air 6 m Pump Lake

I want you to draw the HGL and EGL using the second picture.

A pump delivers water from a tank (A)X water surface elevation-110m) to tank B (water surface elevation= 170m). The suction pipe is 45m long and 35cm in diameter the delivered pipe is 950m long 25cm in diameter. Loss head due to friction hf1 = 5m and h2 3m If the piping are from pipe(1)= steel sheet metal pipe(2)= stainless – steel Calculate the following i) ii) The discharge in the pipeline The power delivered by the pump.

Consider a desired pump operating condition which adds 35 psi at a flow rate of 500 gpa to water. Ignore any changes in Kinetic or potential energy and assume isothermal flow (ie. Internal energy is constant, this is normal assumption we make when analyzing fluid flows in piping systems). Apply the energy balance only across the pump starting with full energy balance and simplifying to solve for the pump head symbolically. Then begin careful of unit, solve for pump head in feet. Given erosion 500 gpm P=62 lbs/ft^3 A- 10.5 ft B- 100.8 ft C- 50.1 ft D-80.7 ft

Give detailed solution,Only Handwritten.

10.0 m 200 m 2. An old western town has a water tower to deliver water to the residents. Pictured above is the water tower. The water tower is closed but there is a section of air that is atmospheric pressure just above the water. The corsss ectional area at point 2 is 4.75 x 10 m. The cross sectional area fot the water tower is very large. What is the speed of the water coming out of the pipe at point 2? (density of water = kg/m³) 3. On a vacation trip up in Oregon my boys decided to build a 10 kg raft that they made out of driftwood. 1000

Figure below shows the performance curve family of Model 5009 Centrifugal pumps of Taco Pump Inc., running at a fixed speed of N = 1160 rpm. For the pump with the impeller diameter D = 8.625 in., you are asked to determine the best efficiency point (BEP) of the given pump. What is the pump efficiency at BEP? HEAD IN FEET 50 0 0 0 0 40 20 10 O 81% 8.625" 30 (219mm). O 51% O 71% ○ 61% O Taco L/SEC 5 9.25" (235mm) 8.00" (203mm) 7.375" (187mm) 6.75" (171mm) 0 10 15 125 Model 5009 FI & CI Series 20 25 CURVES BASED ON CLEAR WATER WITH SPECIFIC GRAVITY OF 1.0 8 8 52 75% 77% 30 79% 1160 RPM FEBRUARY 19. 2002 35 40 45 REQUIRED NPSH olº 1.5HP (1.1KW) dot 17% Curve no. 2140 Min. Imp. Dia. 6.75" Size 6 x 5 x 9.0 50 55 60 75% 72% 250 375 500 625 FLOW IN GALLONS PER MINUTE 8% 2HP(1.5KW) 750 %09. 55% (2.2KW) 3HP 7.5HP(5.6KW) 2015 do 35% 875 FEET 15 12 -9 6 SHP(3.7KW) 3 0 10 8 NPSH 1000 HEAD IN METERS 5 KPo 45 -36 27 18 9 -0 100 -80 60 -40 2 -20 8 HEAD IN KILOPASCALS