Describe the operation of the eight-bit comparison arrangement in Figure below for the following cases: (a) A7 A6 A5 A4 A3 A2 A1 A0 = 10101111; B7 B6 B5 B4 B3 B2 B1 B0 = 10110001 (b) A7 A6 A5 A4 A3 A2 A1 A0 = 10101111; B7 B6 B5 B4 B3 B2 B1 B0 = 10101001 MSB Input A A7 A8 As A MSB Input B By Be B5 BA LSB Input A A3 A2 A₁ A LSB Input B B3 B2 B₁ Bo +5 V A3 A₂ A A B3 B₂ 8, Bo A3 A₂ A₁ A 83 82 B, Bo A>B) A>B (A>B) IC 7485(2) (A=B) A=B IC 7485(1) 1(A=B) (A

For the three code words:C1= [110110011], C2= [100101100]andC3=[111100101]. Determine the possible error detection and the possible error .correction

Convert the following one's complement signed 8-bit numbers into decimal. Be sure to show all of your work. (a) (0000 1010) 2 (b) (1111 1010) 2 (c) (0111 1010) 2 (d) (1111 1111) 2

Add the following signed 5-bit 2's complement binary numbers and convert the sum to a decimal (bose ten) numbe a) e0111 + 00011 this sum in base ten: b) 11101 + 00011 this sum in base ten: c) 10001 + 10001 this sum in base ten: d) 10000 + 100ee this sum in base ten: e) 10101 + 01010 this sum in base ten: LLL

In single precision (IEEE-754 standard), 8 bits are used for storing the exponent (the bias is 127), and 23 bits are used for storing the mantissa.  (a) What are the smallest and the largest positive numbers that can be stored in single precision? (b) What is the smallest value of the mantissa that can be stored?

What is the largest positive number one can represent in  a 16-bit 2's complement code? Write your result in decimal.A - 32768B - 32768 decimalC - 32767 DecimalD - 32767

THe adjusted exponent in 64-bit is(A) - E ' = 1023-exponent(B) - E ' = 1024-exponent(C) - E ' = 257+exponent(D) - E ' = 1023+exponent

H - For the IEEE 754 single-precision floating point, write the hexadecimal representation for the following decimal values: (i)–1.0 (ii)– 0.0 (iii)256.015625

3. Perform the following operations involving four-bit 2's complement numbers and indicate whether arithmetic overflow occurs. Verify your answers by converting to decimal sign- magnitude representation. 0011 +0100 0101 +0110 0101 + 1010 1011 +0110 1101 + 1100 1011 + 1010

The modulus for the field GF(25) is x5+x2+1 and its elements are all five-bit strings. Calculate each of the following and enter your answer in exactly five bits (Example, 01101). 1. 11111 + 00001 2. 00011 x 00011 3. 01100 x 01100