Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN: 9780133923605
Author: Robert L. Boylestad
Publisher: PEARSON
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- n a self-biased FET amplifier given in the figure, Vdd = 20V, Rs = 1k ohm, VGSq = 2.6mA. The transistor has a specific value of Idss = 8 mA, Vp = -6V and gos = 25 microS. 12 mV a.c. to transistor input. What is the Rd resistance value so that the output voltage is -24.85 mV when voltage is applied? The answer is between 3.3 k ohms and 4.6 k ohms.arrow_forwardSolve as a function or equation of the transistor small signal parametersarrow_forwardConsider the JFET amplifier in the Figure below with transistor parameters loss = 6 mA, VGS (OFF) = -3 V and VA = 100 V. Let VDD = 10 V. a) Determine RD and VGs such that ID = 4 mA and VDs = 6 V. b) Determine gm and ro. c) Determine the small-signal voltage gain Av = vo/Vi. VDD Vj + VGS + H + VGS ww + UDS VOarrow_forward
- Prelab: Using the BJT large signal model for the circuit in Figure 1, determine the Vub voltage required to drive a collector current of I, = 0.5 mA. Use RB = 220 kN, Rc = 2.05 kN, RE = 1.05 kN, and Vee = 5V. Assume Is = 50nA and ß = 250. (Hint: Find Vbe using Ic, then use KVL to find Vbb, remember that Ib can be found using the Ic/ ß relationship) RC Voc R3 bb RE Figure 1 NPN BJT under DC Biasarrow_forward1. Design a fixed bias-transistor circuit using VBB = Vcc = 10 V for a Q-point of Ic = 5 mA and VCE_ 4 V. Assume BDc = 100.The design involves finding RB and Rc.arrow_forwardA transistor amplifier circuit is biased so that the quiescent point is to the far left of the load line midpoint. What do you expect to occur when the input voltage begins to vary? O The output voltage will be distorted on the bottom because it will hit the lower limit for VCE before the input voltage arrives at its peak. The output voltage will be distorted on the top because it will hit the upper limit for VCE before the input voltage arrives at its peak. O The output voTransistor's output voltage will look like the input voltage amplified and inverted. The output voltage will be zero (flat).arrow_forward
- 2. The parameters of the transistor as shown in the figure below are ß = 100 and VA = 100V. a. Find the dc voltages at the base and emitter terminals. b. Find Rc such that VCEQ = 3.5V. c. Assuming Cc and CE act as short circuits, determine the small-signal voltage gain Av = Vo/Vs. d. Repeat part (c) if a 5000 source resistor is in series with the vs signal source. V+ = +5 V Rs = 100 £2 www Us Cc RB = 10 ΚΩ I= Iausmi 0.35 mA www RC -000 V=-5 V CEarrow_forwardI need illustrations for these answers.arrow_forwardHand Calculation: Since you now have the values of R1 and R2 resistors, obtain numeric value of voltage gain Av=Vo/Vi, and numerical values of input and output resistances Ri and Ro. Note that you need to DC analysis first. Do a hand calculation and calculate the DC collector current or IC. This is needed in order to calculate the small signal parameters gm and rπ and in turn to obtain the Av , Ri and Ro Hence, first perform a DC analysis (use the circuit in Figure 1 and take all capacitors open) and assume your transistor has a β=140.arrow_forward
- Q3) For the regulator circuit shown in figure below, Vin-15 V, Rs-10 2, Vz-9.1 V, VBE=0.8V, and R=40 2. What are the values of output voltage, input current, the load current, and collector current. 102016 2-8594 Vin R$ Ⓡ R₂ Voutarrow_forwardFor the given Common Emitter NPN Amplifier, the transistor made of Germanium diodes, BDC-80, Vcc Rc-3.9 K2, RE-0.68 KQ. a) Name the type of biasing used in the above circuit? 1 = 16 volts, R= 62 KQ, Rz 9.1 K R, Rc Cs b) Find VE? Find VCE? d) Find Vc? e) What is the name of the capacitors C1, C3 and C2?arrow_forwardCan someone explain this problem to me. I don't know how to get to the answer that is given.arrow_forward
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