depth of an oil well is 17,500 feet. The pressure of the oil at the bottom is the same as that of a 15,500-foot-deep column of saltwater. The oil has a density of 55 lbm/ft3. What is the pressure exerted on the oil in the well's surface? (Sea water density = 63.9 lbm/ft3).

Hello. Our instructor solved this question and subtracted the product of water's height and specific weight from the P1 pressure, as well as oil's. He didn't factor air pressure into the equation. What is the reason why we do not use open air pressure to solve the problem?

It is estimated that 91 percent of an iceberg's volume is below the surface, while only 9 percent is visible above the surface. For seawater with a density of 1025 kg/m³, estimate the density of the iceberg. The density of the iceberg is kg/m³

The open tank filled with a liquid in full as shown in the figure below has the height of h = 6.00 m.  The inclined angle of the inclined wall is  = 45.00 °. The width (perpendicular to the screen) of the inclined wall is w = 20.00 m. The specific weight of the liquid is  = 9.81 kN/m3. (1) For the inclined wall, determine the average pressure on it._________ (kPa)