Define cantilever truss with an example.?

1) A long span open-web steel joist with a span of 70 feet is required to support a floor. The joists are spaced at 3.5 ft apart, the dead load is 15 lb/ft² (not including the self weight), the live load is 80 lb/ft? and the live load deflection is limited to L/360 (which is that used to determine the live load limit - in red/light - based on deflection in the SJI catalogue tables and those limits must be multiplied by 1.5 if L/240 is used). Using the LRFD table provided, select the most economical joist that can be used considering the self weight. The lighter values are the limiting unfactored live load. (Note: longer spans that can support the load can also be used.)

c. Determine critical load and critical stress for the column/axial member. Justify selection of the formulas for the calculationsInformation provided: i) Boundary/end conditions: In this instance, the column is assumed to be fixed at both ends, simulating conditions where the column is integrally connected to the floor slabs above and below, a common condition in many mechanical design contexts. ii) External axial load: Assuming the column supports a floor with a uniformly distributed load, we've calculated the total axial load on the column to be 453.589 kN. iii) Properties of the column: The cylindrical column is composed of steel, a commonly used material with a known Young's modulus (E) of approximately 200 GPa. The steel has a yield stress of around 250 MPa and ultimate stress near 400 MPa. The diameter (d) of the column is 0.3048 m, providing a cross-sectional area (A) of π*(d/2)² = 0.073 m².

Example 8.6 A Weighted Forearm Goal Apply the equilibrium conditions to the human body. -Humerus Problem A W = 47.3 N (11 lb) weight is held in a person's hand with the forearm horizontal, as in Figure 8.11. The biceps muscle is attached d = 0.0302 m from the joint, and the weight is / = 0.351 m from the joint. Find the upward force F exerted by the biceps on the forearm (the ulna) and the downward force R exerted by the humerus on the forearm, acting at the joint. Neglect the weight of the forearm. W Biceps Ulna W (a) (b) Figure 8.11 (a) A weight held with the forearm horizontal. (b) The mechanical model for the system. Strategy The forces acting on the forearm are equivalent to those acting on a bar of length 0.351 m, as shown in Figure 8.1lb. Choose the usual x- and y-coordinates as shown and the axis O on the left end. (This completes Steps 1 and 2.) Use the conditions of equilibrium to generate equations for the unknowns, and solve. Solution ET; = TR + TF + TBB = 0 R(0) + F(0.0302…

A post of No. 2 grade hemlock is 6.0 ft long and has a square cross section with side dimensions of 3.50 in. How much would n be shortened when if is loaded in compression up to its allowable load parallel to the grain?

A alank of wood is fixed to a wall using a hinge. When the angle between the plank and the wall is 45°, a spring is attached to the wood 25cm from the hinge and fixed to the wall so that it is horizontal (Diagram A). The wood is then pushed downwards until it is perpendicular to the wall (Diagram B). The force exerted by the spring, depends on its length. As the spring stretches, the force it exerts increases. A graph showing this relationship is below. 70 Diagram B 60 Diagram A spring 50 90° 20 25cm 45 90° 10 25cm hinge 10 35 15 20 25 30 Spring Length (cm) (a) Calculate the length of the spring in Diagrams A and B. (b) Calculate the torque produced by the spring on the plank of compare the values. around the hinge in 4 oth Diagrams A and B and Force (N)

Answer would be appreciated

show step by step solution so that i can know the process thank yousubject:mechanic of deformable bodies