def ALGORITHM (text): processor := list containing '0' i = 1 while i < length (text): if text[i] == "s": push "s" onto processor else if text[i] == "d": push "d" onto processor else if text[i] == "p": push "p" onto processor else if text[i] == "q": push "q" onto processor else: v = pop from processor v := v * 10 v := v + numeric value of text[i] digit push v onto processor i := i + 1 loop while length (processor) > 1 t2 = processor.pop() c = processor.pop() t1 = processor.pop() if c == "s": push t1 + t2 onto processor else if c == "d": push tl else if c == push tl else if c == "q": t2 onto processor "p": t2 onto processor push t1 / t2 onto processor loop return = pop from processor

Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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Assuming that all indexing operations, as well as the push and pop operations, can be performed in constant time, what is the average time complexity of ALGORITHM?
Pick ONE option
O(1)
O(N)
O(N²)
O(N * log(N))
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Select the snip mode using the Mode button or click
Transcribed Image Text:Assuming that all indexing operations, as well as the push and pop operations, can be performed in constant time, what is the average time complexity of ALGORITHM? Pick ONE option O(1) O(N) O(N²) O(N * log(N)) New Mode Select the snip mode using the Mode button or click
def ALGORITHM (text):
processor := list containing '0'
i : = 1
while i < length(text):
if text[i]
== "s":
push "s" onto processor
"d":
else if text[i]
else if text[i]
push "d" onto processor
else if text[i]
"p":
push "p" onto processor
"q":
push "q" onto processor
else:
==
i := i + 1
loop
loop
==
v := pop from processor
V = V * 10
v := v + numeric value of text[i] digit
push v onto processor
==
while length (processor) > 1
t2 = processor.pop()
c = processor.pop()
t1 = processor.pop()
if c == "s":
push t1 + t2 onto processor
else if c == "d":
-
push tl t2 onto processor
else if c == "p":
push t1 * t2 onto processor
else if c == "q":
push t1 / t2 onto processor
return := pop from processor
Transcribed Image Text:def ALGORITHM (text): processor := list containing '0' i : = 1 while i < length(text): if text[i] == "s": push "s" onto processor "d": else if text[i] else if text[i] push "d" onto processor else if text[i] "p": push "p" onto processor "q": push "q" onto processor else: == i := i + 1 loop loop == v := pop from processor V = V * 10 v := v + numeric value of text[i] digit push v onto processor == while length (processor) > 1 t2 = processor.pop() c = processor.pop() t1 = processor.pop() if c == "s": push t1 + t2 onto processor else if c == "d": - push tl t2 onto processor else if c == "p": push t1 * t2 onto processor else if c == "q": push t1 / t2 onto processor return := pop from processor
Expert Solution
Step 1

In this question, it is asked to calculate the time complexity of the given code segment

Given:  All pop and push operations take linear time.

Length of the text is considered to N.

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