Deborah wants to estimate the percentage of people who eat fast food at least once per week. She wants to create a 90%confidence interval which has a margin of error (or ME) of at most 3%. How many people should be polled to create the confidence interval? z0.10 z0.05 z0.025 z0.01 z0.005 1.282 1.645 1.960 2.326 2.576 Use the table of values above. Select the correct answer below:   165   188   271   457   752

If n = 20, the sample mean = 250, SD = 15, SEM = 3.354, what is the confidence interval (using 95% confidence level). What percent confidence do you have that the population mean is between what two values

Tina catches a 14-pound bass.  She does not know the population mean or standard deviation.  So she takes a sample of five friends and they say the last bass they caught was 9, 12, 13, 10, and 10 pounds.  Find the t and calculate a 95% (α = .05) confidence interval.

Lexi of Arm End  insurance ,was hired to estimate the proportion of patients that had paid their Bill's on time.  She took a random sample of 100 such patients  and found that 85 of them had paid their Bill's on time. Help her find 96% confidence  interval  for population proportion. 1. What is the X and is the "n"  sample size? What is the point estimate for the population proportion? 2 Estimate the 96% confidence interval for the proportion  of people that paid their bills on time . 3 What is the standard  error for the population proportion ? 4 The margin of error for the population  proportion, is 4%