Deborah wants to estimate the percentage of people who eat fast food at least once per week. She wants to create a 90%confidence interval which has a margin of error (or ME) of at most 3%. How many people should be polled to create the confidence interval? z0.10 z0.05 z0.025 z0.01 z0.005 1.282 1.645 1.960 2.326 2.576 Use the table of values above. Select the correct answer below:   165   188   271   457   752

Q: Suppose​ that​ 18% of a random sample of 2307 Miami residents said that they will donate blood in…

A: we have given that sample size =n=2307 ,sample proportion =p^=18%=0.18

Q: The student government association at a university wants to estimate the percentage of the student…

A: As per guideline expert have to answer first question only.

Q: employment. graduatés from the year 2016 were asked questions about Employment College students'…

A: Given : Sample Size, n = 1500 confidence level,c=0.95 Significance level, α…

Q: You sample 36 families to find out how much they spent on groceries last month. Your sample mean is…

A: Given data,n=36x=540s=82α=0.05

Q: Suppose we wanted to estimate the average amount of sleep (in hours) a college student gets a night.…

A: Confidence interval : Confidence interval is a range of values it contains the true population…

Q: Construct a 95% confidence interval for the proportion of adults from the East who say traffic…

A: n = 400 p = 0.34

Q: A 95% confidence interval for the mean score of all bowlers based on n = 40 is (131.28, 138.72). The…

A: From the given statement we want to know is it true or false.

Q: Chronic Ilness - A recent survey asked a large sample of U.S. adults about their health. The report…

A: Proportion is almost similar to the concept of probability. Proportion is a fraction of population…

Q: Let's say you survey a random sample of people. You find that 53% prefer apples over oranges. You…

A: given data  p^ = 0.5390% ci for p is : (0.448,0.612)based on this ci we have to find the given…

Q: Kim wants to determine a 80 percent confidence interval for the true proportion of high school…

A: Given: Margin of error, E=0.04 Confidence level=80%

Q: Believe it or not, there are some people who dont think that Duke will win the NCAA tournament this…

A: Obtain the 90% Confidence Interval for the IQ of DDs.   The 90% Confidence Interval for the IQ of…

Q: We wish to estimate what percent of adult residents in a certain county are parents. Out of 600…

A:

Q: Translate the statement into a confidence interval. Approximate the level of confidence. In a survey…

A:

Q: Suppose that the a college wants to have an idea of the average SAT score of the incoming freshman…

A: The confidence level is 0.90, the standard deviation is 310 and margin of error E is 50.

Q: Find the 95% confidence interval for the proportion of customers planning to buy the shoes, and…

A: Provided data is, Mary was successful and collected 600 responses in time. 195 of the surveyed…

Q: Translate the statement into a confidence interval. Approximate the level of confidence. In a survey…

A: Given info: In a survey of 1002 adults in a country, 79% said being able to speak the language is at…

Q: A researcher wanted to check whether the percentage of Canadian adults with obesity has decreased in…

A: Number of Canadian adults in 2005= 75 Number of Canadian adults in 2009 = 120   significance level =…

Q: You have constructed the following 95% confidence interval about the population mean: [80, 100] This…

A: We have given that,  The 95% confidence interval about population mean = [ 80, 100]. This indicates…

Q: The figure to the right shows the results of a survey in which 2500 college graduates from the year…

A:

Q: You are trying to calculate a confidence interval to estimate a population mean. After performing…

A:

Q: We wish to estimate what percent of adult residents in a certain county are parents. Out of 600…

A: Obtain the 95% confidence interval for the true proportion of adult residents who are parents in…

Q: An environmentalist wants to find out the fraction of oil tankers that have spills each month.…

A:

Q: We wish to estimate what percent of adult residents in a certain county are parents. Out of 100…

A: According to the given information, we have Out of 100 adult residents sampled, 88 had kids. 99%…

Q: Construct the 90% confidence interval for the difference p1-p2 when x1=45, n1=85, x2=20, and n2=65.…

A: Given Information: x1=45n1=85x2=20n2=65c=90%=0.90

Q: The figure to the right shows the results of a survey in which 1500 college graduates from the year…

A: For proportion of college students that expect to stay at their first employer for 3 or more years…

Q: Think about a population mean that you may be interested in and propose a confidence interval…

A: Given sample, 2, 0, 1, 5, 0, 2, and 3. To estimate the confidence interval for a population mean we…

Q: Student 1 Student 2 Student 3 Student 4 Student 5 Student 6 Student 7 Student 8 Student 9 Height…

A: Given α=0.05nH=9nW=9 Define: X¯H=mean height of the sample of students X¯W=mean weight of the…

Q: You are interested in constructing a 99% confidence interval for the proportion of all caterpllal…

A:

Q: Cora wants to determine a 90% confidence interval for the true proportion of high school students in…

A: Confidence level=90%Margin of error(E)=0.02Assuming that we have no prior estimate of the proportion…

Q: We wish to estimate what percent of adult residents in Ventura County like chocolate. Out of 600…

A: It is needed to estimate the percent of adult residents in Ventura County like chocolate.

Q: If n = 440 and p = 0.52, construct a 90% confidence interval. %3D Give your answers to three…

A: Given information- Sample size, n = 440 Confidence level, c = 0.90 So, significance level (α) = 0.1…

Q: Sally is analyzing wheat production. She sampled 700 wheat farmers from across the state. She found…

A:

Q: Let's say you survey a random sample of people. You find that 53% prefer apples over oranges. You…

A: You find that 53% prefer apples over oranges from survey.  ∴ p^ = 0.53 90% ci for p = (0.448,0.612)…

Q: At a traffic stop on a Saturday night 30% of 40 drivers were intoxicated. What is the 99% confidence…

A:

Q: Keisha wants to estimate the percentage of managers at her company that hold an MBA. She surveys 320…

A: Givensample size(n)=320x=72sample proportion(p^)=xn=72320=0.225confidence level=90%

Q: Using an ? = 0.04, a confidence interval for a population proportion is determined to be 0.55 to…

A: Answer  Given  level of significance [α] =0.04 a confidence interval for a population proportion is…

Q: Let's say you survey a random sample of people. You find that 53% prefer apples over oranges. You…

A: p^ = 0.5390% ci for p is : (0.448,0.612)based on this ci we have to find the given statement is true…

Q: Suppose we wish to construct a 95% confidence interval for the population proportion of fans in…

A: Given that, Total fans = 200 130 answered yes 95% confidence level

Q: What is the probability for a z-score of 1.597 What is the confidence interval for a study if the…

A: Given data: 1.What is the probability for a z-score of 1.597 2.What is the confidence interval for a…

Q: Virginia wants to estimate the percentage of students who live more than three miles from the…

A: We have given that Margin of error (E) = 5% = 0.05Significance level (α) = 1 - 0.95 = 0.05 Hence,…

Q: According to a poll, 86% of California adults (434 out of 506 surveyed) feel that education is one…

A:

Estimation

A new framework of data analysis where the new statistical methods are used for interpreting the results and analyzing the data is known as estimation in statistics.