Lexi of Arm End  insurance ,was hired to estimate the proportion of patients that had paid their Bill's on time.  She took a random sample of 100 such patients  and found that 85 of them had paid their Bill's on time. Help her find 96% confidence  interval  for population proportion. 1. What is the X and is the "n"  sample size? What is the point estimate for the population proportion? 2 Estimate the 96% confidence interval for the proportion  of people that paid their bills on time . 3 What is the standard  error for the population proportion ?

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Lexi of Arm End  insurance ,was hired to estimate the proportion of patients that had paid their Bill's on time.  She took a random sample of 100 such patients  and found that 85 of them had paid their Bill's on time. Help her find 96% confidence  interval  for population proportion.

1. What is the X and is the "n"  sample size?

What is the point estimate for the population proportion?

2 Estimate the 96% confidence interval for the proportion  of people that paid their bills on time .

3 What is the standard  error for the population proportion ?

4 The margin of error for the population  proportion, is 4%

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Hi! Thank you for the question, As per the honor code, we are allowed to answer three sub-parts at a time so we are answering the first three as you have not mentioned which of these you are looking for. Please re-submit the question separately for the remaining sub-parts.

 

Given,

n = 100

x = 85

level of significance  = 0.04

 

 

 

 

To find,

1) x=?, n = ?, p = ?

2) 96% confidence interval

3) standard error

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