data set about speed dating includes "like" ratings of male dates made by the female dates. The summary statistics are n= 194, x= 5.81, s= 1.95. Use a 0.05 significance level to test the claim that the opulation mean of such ratings is less than 6.00. Assume that a simple random sample nat addresses the original claim. been selected. Identify the null and alternative hypotheses, test statistic, P-value, and state the final conclus What are the null and alternative hypotheses? O A. Ho: H=6.00 H: u#6.00 O B. Ho: u<6.00 H: p> 6.00 OC. Ho: H= 6.00 H:>6.00 O D. Ho: =6.00 H: p<6.00 Determine the test statistic. (Round to two decimal places as needed.) Determine the P-value. (Round to three decimal places as needed.) State the final conclusion that addresses the original claim. v 6.00. Ho. There is evidence to conclude that the mean of the population of ratings is not sufficient sufficient Click to select your answer(s).

The average retirement age in America is 66 years old. Do small business owners retire at an older average age? The data below shows the results of a survey of small business owners who have recently retired. Assume that the distribution of the population is normal. 63, 74, 59, 64, 74, 60, 71, 67, 65, 70, 63 What can be concluded at the the � = 0.05 level of significance level of significance? For this study, we should use     The null and alternative hypotheses would be:       �0:                   �1:               The test statistic     =  (please show your answer to 3 decimal places.) The p-value =  (Please show your answer to 4 decimal places.) The p-value is     � Based on this, we should      the null hypothesis. Thus, the final conclusion is that ... The data suggest the populaton mean is significantly older than 66 at � = 0.05, so there is sufficient evidence to conclude that the population mean retirement age for small business owners is older than 66. The data suggest…

A clinical researcher performs a clinical trial on 12 patients to determine whether a drug treatment has an effect on serum glucose. The sample mean glucose of the patients before and after the treatment are summarized in the following table. The sample standard deviation of the differences was 6.   Sample mean glucose (mg/dL) Before treatment 114 After treatment 108 What type of hypothesis test should be performed?Select: Left-tailed z-test Unpaired t-test Two-tailed z-test Paired t-test    What is the test statistic?   What is the number of degrees of freedom?   Does sufficient evidence exist to support the claim that the drug treatment has an effect on serum glucose at the α=0.05 significance level? Select: _____Yes  OR  _____No

Please answer FULL question

Perform a hypothesis test to determine whether there is a difference in the mean attendance of teams between the two groups created in Part F. Use a 0.05 level of significance in your testing procedures.   Hint: When calculating your pooled sample variance and your test statistic, assume the Top 10 data is sample 1 and the Bottom 10 data is sample 2.   Decision Rule -t <   or  t >   =   REJECT H0 Value of Pooled Sample Variances   Value of test statistic   Decision: enter Reject or Do Not Reject     Is there a difference in the mean attendance between the two groups assuming a 0.05 level of significance? Enter Yes or No.     Another variable that can impact attendance is the team's win-loss record. Teams that are winning more games are thought to have increased attendance as fans prefer to see their home team "win" rather than "lose" (although for some teams such as the Chicago Cubs, this is not always an established relationship!).  Create 2 samples…

Use a 0.05 significance level to test the claim that males and females have the same mean BMI Male BMI n=80 * = 26.3 s = 5.4 Female BMI n=61 I = 28.4 s = 7.4

Salaries of 34 college graduates who took a statistics course in college have a mean, x, of $67,400. Assuming a standard deviation, o, of $15,845, construct a 90% confidence interval for estimating the population mean u.

The summary statistics are n=85, x=3.93, s=0.63. Use a 0.01 significance level to test the claim that the population of student course evaluations has a mean equal to 4.00. identify null/ alt hypothesis, test statistic, P- value, and state final conclusion that addresses the original claim

Help please

A pipes manufacturer makes pipes with a length that is supposed to be 12 inches. A quality control technician sampled 35 pipes and found that the sample mean length was 12.05 inches and the sample standard deviation was 0.13 inches. The technician claims that the mean pipe length is not 12 inches. What type of hypothesis test should be performed? Two-tailed t-test Two-tailed z-test Left tailed t-test Left tailed z-test What is the test statistic? What is the number of degrees of freedom? Does sufficient evidence exist at the α=0.01 significance level to support the technician's claim? Yes or No