Vertical highway curve: Given PVI at 128 + 00, L = 1,000 ft, g1 = -5%, g2 = +4%, and PVI elevation = 457.25 ft, compute the elevations of the curve low point and the 100 ft stations (means stations 124+00, 125+00, etc. until reaching the end of the curve) as well as for the beginning and end of the curve.

2. Compute by hand and tabulate station elevations and the 1st and 2nd differences for an equal tangent parabolic (vertical) curve for the following data: A +3.50% (g1) grade meets a -4.00% (g2) grade at Station 12+65 (the PVI). The PVI Elevation = 300.00'. Length of Curve = 750'. Calculated elevations for full stations between the BVC and the EVC. Also, calculate the station and elevation of the curve for the PVI, BVC, EVC and the High Point. Place all the information in station order in a properly labeled and organized table using the exact format shown in the last slide of the Application of Vertical Curves Video. Show all elevations to 3 decimal places. Provide a page sized detailed and labeled sketch of the profile of the curve. Deliverables: Your calculations, sketches and tables should be submitted by the syllabus deadline as a properly named single PDF document. The order for the information in the submission PDF is to be as follows: Problem 1 Hand Calculations Problem 1…

Two highway tangents intersect with a right intersection angle of 23º40' at station 73+61.28ft.If a 5º00 'horizontal circular curve is to be used to connect the tangents, computer R, T, Land E for the curve.

Given an equal tangent vertical curve, in feet, with the following known information: • STA A (Beginning of Curve) = 13+00 o Elevation A = 220.00 feet • L= 900.0 feet G1 = -4.25% and G2 = +3.25% What is elevation of the low point on the curve, in feet? rrect Answer O 209.16 u Answered O 220.00 O 209.76 O 215.51