CS2+302 CO₂+2SO₂ If 6.0mol of CS2 and 6.0 mol of O₂ react to form moles of the products. You can solve for either product to help you figure out which compound is the limiting reagent. You may need to solve for the other product to find the answer to the last 2 boxes. choose your answer... is the limiting reactant and it produced choose your answer... may require you to solve for both products to find the right answer in the drop down below. choose your answer... choose your answer... CS₂ 0₂ ^ choose your answer... choose your answer... 3.00mol 4.00mol 6.00mol choose your answer.... choose your answer... choose your answer... CO₂ SO₂ V.This problem

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Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
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CS2+302 CO₂ +2SO₂
If 6.0mol of CS2 and 6.0 mol of O2 react to form moles of the products.
You can solve for either product to help you figure out which compound is the limiting reagent. You may need to solve for the other product to find the answer to the last
2 boxes.
choose your answer.... Vis the limiting reactant and it produced choose your answer.....
may require you to solve for both products to find the right answer in the drop down below.
choose your answer...
choose your answer...
CS₂
02
choose your answer...
choose your answer...
3.00mol
4.00mol
6.00mol
✓of
choose your answer..... V This problem
choose your answer...
choose your answer...
CO₂
SO₂
Transcribed Image Text:CS2+302 CO₂ +2SO₂ If 6.0mol of CS2 and 6.0 mol of O2 react to form moles of the products. You can solve for either product to help you figure out which compound is the limiting reagent. You may need to solve for the other product to find the answer to the last 2 boxes. choose your answer.... Vis the limiting reactant and it produced choose your answer..... may require you to solve for both products to find the right answer in the drop down below. choose your answer... choose your answer... CS₂ 02 choose your answer... choose your answer... 3.00mol 4.00mol 6.00mol ✓of choose your answer..... V This problem choose your answer... choose your answer... CO₂ SO₂
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