Structural Analysis
6th Edition
ISBN: 9781337630931
Author: KASSIMALI, Aslam.
Publisher: Cengage,
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- Calculate the hydraulic mean radius Manning's equation for a trapezoidal channel to carry 200 cumec discharge laid at a slope of 30 cm/km with side slope 1.5:1 at a flow velocity of 2 m/sec. Take rugosity factor of 0.017.arrow_forwardA hydraulic Jump occurs in a trapezoidal channel having b=6ft, m=2, and Q=200cfs. The flow depth just before the jump is 1 foot. What is the flow depth after the jump? What is the headloss due to the jump? What type of jump is it? What is the length of the jump?arrow_forwardProvide handwritten answer pleasearrow_forward
- Water flows in a 1.5 m wide rectangular channel with a flowrate of Q = 0.8 m3 /s and upstream depth of y1 = 0.75 m. Determine the flow velocity and the surface elevation at section 2.arrow_forwardDetermine the depth of the trapezoidal canal with sides sloping at 60ᵒ with the horizontal in order to have a minimum seepage. The canal is to carry a discharge of 25 m3/s with an average velocity of 1 m/s. Note: for minimum seepage = bottom width = 4(depth)(tanθ/2)arrow_forward5. A tar coated (n = 0.014) triangular channel has 45ᵒ sides and slope of 0.0004. Compute the normal depth for a discharge of 140 ft3/s.arrow_forward
- 4.58. A trapezoidal canal has a longitudinal slope of 1%, side slopes of 3:1 (H:V), a bottom width of 3.00 m, a Man- ning's n of 0.015, and carries a flow of 20 m³/s. The depth of flow at a gaging station is observed to be 1.00 m. Answer the following questions: (a) What is the normal depth of flow in the channel? (b) What is the critical depth of flow in the channel? (c) Classify the slope of the channel and the water sur- face profile at the gaging station.arrow_forward: The width of a horizontal, rectangular channel is reduced from 3.5 to 2.5 m and the floor is raised by 0.25m in elevation at a given section. At the upper stream section the depth of flow is Im and the KE correction factor is 1.15. If the drop in water level at the contraction is 0.20m. Calculate loss is i) Discharge if energy • zero. ") Discharge if energy loss is 10th of the upper stream velocity head. KE correction factor for contracted section is unity. 2m y₁ 0.2m y: 2 0.25 m. 3.5 2.5marrow_forwardThe base of the artificial channel has a bottom width of 3m and sides with a slope of 1 vertical to 2 horizontal. The depth of water being predicted/estimated is 1.2m when the discharge is 3.51m3/s. Using Manning's equation with n = 0.022 a. Calculate the slope of the channel bed.b. Calculate the discharge in m3/s when the depth of flow is 1.3m.arrow_forward
- For #5-7, assume there is a creek with a width of 4.6 m, depth of 23 cm, slope of 0.001 m/m, and discharge of 0.13 m³/s. 5. Assuming a rectangular cross section, what is the hydraulic radius of the creek to the nearest cm? 6. What is the average flow velocity to the nearest cm/s? 7. And what is the channel's Manning's roughness coefficient (using SI units) to the nearest hundredth?arrow_forwardA flow of 30 m3 /s occurs in a trapezoidal channel having a base width of 3 m, side slopes 1 vertical to 2 horizontal. Determine the critical depth, yc.arrow_forward2- A 6-m wide concrete-lined trapezoidal channel (n = 0.013) has a sidewall slope of 1V:1.5H, a longitudinal slope of 0.0005, and carries a discharge of 20 m³/s. Calculate: a) normal depth, Yni b) critical depth, yo c) determine the flow regime based on comparison of yn and ycarrow_forward
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