Structural Analysis
6th Edition
ISBN: 9781337630931
Author: KASSIMALI, Aslam.
Publisher: Cengage,
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- Specific energyA horizontal rectangular channel is 12 feet wide and carries a flow rate of 60 cfs. A hump that is 0.5 feet high is placed in the flow path. a. If the normal depth of flow is 1.5 feet, what is the depth of flow over the hump? b. If the normal depth of flow is 0.5 feet, what is the depth of flow over the hump?arrow_forward2- A rectangular channel has a width of 6 m, carriers a discharge of 24 m³/s with a depth of 3.2 m at Section 1. At Section 2, the flow experiences a smooth and gradual contraction with a minimum width of Bmin to form a critical condition. Assuming energy loss equal to 20% of velocity head at Section 1: a) Calculate the minimum channel width (Bmin) at Section 21 b) Calculate the force (F) exerted from water on the wall by employing the momentum equation 1 B₁ F= F Top veiw 2 Bmin Y1 Side veiwarrow_forwardCalculate the discharge through the channel and the floodway (shown in the Figure below) for steady uniform flow, with S = 0.0009 and y = 8 ft. n = 0.025 ne = 12 m 5 m n=0.040 √ [EXP²] + Р Paper 120 m ZAZ Use the following equivalent channel roughness formula due to Pavlovskii (1931)* Side slopes 1:1 For 25,000 cfs flow through the channel above, find the depth of flow in the floodway when the slope of the energy grade line is 0.0004.arrow_forward
- the flow rate is 1.2 m3/s per meter of channel width. (a) Compute the velocity and water depth at the top of the budge (hmax= 0.1 m). Characterize the flow there. (b) Rework the problem for a flow rate three times as large.arrow_forwardThe base of the artificial channel has a bottom width of 3m and sides with a slope of 1 vertical to 2 horizontal. The depth of water being predicted/estimated is 1.2m when the discharge is 3.51m3/s. Using Manning's equation with n = 0.022 a. Calculate the slope of the channel bed.b. Calculate the discharge in m3/s when the depth of flow is 1.3m.arrow_forwardSolve 6.3 onlyarrow_forward
- 2- A 6-m wide concrete-lined trapezoidal channel (n = 0.013) has a sidewall slope of 1V:1.5H, a longitudinal slope of 0.0005, and carries a discharge of 20 m³/s. Calculate: a) normal depth, Yni b) critical depth, yo c) determine the flow regime based on comparison of yn and ycarrow_forwardWater discharges in too wide rectangular channel slope =0.01 Just apstream the weir where the water depth is 2.5m the flow rate is 5m ^ 3/s As per meter width as shown below Assume n = 0.015 and neglected losses. 1. Find the normal depth, the critical depth and the critical slope? 2. Use the specific energy equation to find the weir height such that the flow over the wer is critical? 3. What water surface profile exists upstream the weir and locate the distance upstream the weit where the water depth equals the normal depth ?arrow_forwardA rectangular concrete channel (n = 0.014) has a bottom width of 5.05 m and a longitudinal slope of 0.002. Compute the discharge rate and velocity for a water depth of 2.34 m. Compute normal depth, critical depth, and critical slope for a discharge of 6.67 m³/s.arrow_forward
- Q7: The channel shown in the figure and has a surface of flout finalized concrete 0.1m per 100m of length calculate the discharge (Q) and Froude number (Fr) for a depth of 1.5m, assume n-0.0015 determine Fr is critical, subcritical or supercritical? y=D=1.5m h -3.0m 3 2arrow_forwardAns. 1.941m/s I need solution #hydraulicsarrow_forwardWater is discharged under a sluice gate at a rate of 75 m3 /s into a frictionless, horizontal, rectangular channel, 6 m wide. The depth just downstream of the gate is 1.25 m. Determine the depth just upstream of the gate opening The Froude number upstream and downstream of the sluice gatearrow_forward
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