Create 1 Program,  in C++, to Solve Engineering Problems. Your programs must include the following elements: 1. Welcome Message 2. Problem Description Message (background, required inputs & expected results) 3. Set/Capture Input Data 4. Perform the Main Process (corresponds to the Engineering Problem) 5. Display Results, feedback, and Comments (Based on results) 6. Goodbye Message Rules: - You can select your Engineering Problems from the Engineering Problems Source document - You must select two different Problems from the source document. - You can select only available problems that were not already selected by another group, selection is on first-come, first-serve basis. - Problems Selection (booking) will be done in the Telegram Group. - After 7 days, groups that did not select problems, will be assigned problems at random Bonuses: - Include Validation (whenever User input is involved) - Solve Multiple Engineering Problems in one program (user can select from main menu) - Add export data option to write results/findings into an external document - Include Plotting/Visualization in your program (using graphics libraries) - Add main menu options, i.e. select program, export data, plot data, restart, quit, etc. - Use advanced/new concepts not taught in class - Any other feature (code readability, good UI, Processing effects, etc.)

Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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Create 1 Program,  in C++, to Solve Engineering Problems.
Your programs must include the following elements:
1. Welcome Message
2. Problem Description Message
(background, required inputs & expected results)
3. Set/Capture Input Data
4. Perform the Main Process
(corresponds to the Engineering Problem)
5. Display Results, feedback, and Comments
(Based on results)
6. Goodbye Message
Rules:
- You can select your Engineering Problems from the Engineering Problems Source document
- You must select two different Problems from the source document.
- You can select only available problems that were not already selected by another group,
selection is on first-come, first-serve basis.
- Problems Selection (booking) will be done in the Telegram Group.
- After 7 days, groups that did not select problems, will be assigned problems at random
Bonuses:
- Include Validation (whenever User input is involved)
- Solve Multiple Engineering Problems in one program (user can select from main menu)
- Add export data option to write results/findings into an external document
- Include Plotting/Visualization in your program (using graphics libraries)
- Add main menu options, i.e. select program, export data, plot data, restart, quit, etc.
- Use advanced/new concepts not taught in class
- Any other feature (code readability, good UI, Processing effects, etc.) 

Cartesian Vector Notation :
1.2i – 0.6j – 3k
FAB = FAB
/1.2² + (-0.6)² + (-3)²
= 0.3578Fgi – 0.2683F,j – 0.8944FAK
0.6і - 0.9ј — 3k
FAC = FAC
= 0.1881F,ci+ 0.2822Fxcj – 0.9407F,k
V0.6? + 0.9² + (-3)²
F= 17.5 kN
0.3 m
-1.2i + 0.3j – 3k
FAD = FAD
=-0.3698Faņi + 0.09245F,pj – 0.9245F,,K
|(-1.2)² + 0.3² + (-3)²
F= {17.5k} kN
1.2 m
0.9 m
Equations of Equilibrium :
0.9 m
EF = 0; FAg + FAc
+ FAn + F = 0
Fae
(0.3578FA5 + 0.1881FAC – 0.3698FAD)i
3 m
+ (-0.2683FAB + 0.2822F,C + 0.09245FAD)j
ac+
+(-0.8944FAg – 0.9407F,c – 0.9245FAD + 17.5)k = 0
Equating the i, j and k components, we have
0.3578FAn + 0.1881F,c – 0.3698F,p = 0
-0.2683F + 0.2822F,c + 0.09245F,Ap = 0
-0.8944FA – 0.9407F,c – 0.9245F,p + 17.5 = 0
[1]
[2]
[3]
Solving Eqs. [1], [2] and [3] yields
F, = 6.848 kN
Fxc = 3.721 kN
FAD = 8.518 kN
Ans
Ans
AC
Ans
Transcribed Image Text:Cartesian Vector Notation : 1.2i – 0.6j – 3k FAB = FAB /1.2² + (-0.6)² + (-3)² = 0.3578Fgi – 0.2683F,j – 0.8944FAK 0.6і - 0.9ј — 3k FAC = FAC = 0.1881F,ci+ 0.2822Fxcj – 0.9407F,k V0.6? + 0.9² + (-3)² F= 17.5 kN 0.3 m -1.2i + 0.3j – 3k FAD = FAD =-0.3698Faņi + 0.09245F,pj – 0.9245F,,K |(-1.2)² + 0.3² + (-3)² F= {17.5k} kN 1.2 m 0.9 m Equations of Equilibrium : 0.9 m EF = 0; FAg + FAc + FAn + F = 0 Fae (0.3578FA5 + 0.1881FAC – 0.3698FAD)i 3 m + (-0.2683FAB + 0.2822F,C + 0.09245FAD)j ac+ +(-0.8944FAg – 0.9407F,c – 0.9245FAD + 17.5)k = 0 Equating the i, j and k components, we have 0.3578FAn + 0.1881F,c – 0.3698F,p = 0 -0.2683F + 0.2822F,c + 0.09245F,Ap = 0 -0.8944FA – 0.9407F,c – 0.9245F,p + 17.5 = 0 [1] [2] [3] Solving Eqs. [1], [2] and [3] yields F, = 6.848 kN Fxc = 3.721 kN FAD = 8.518 kN Ans Ans AC Ans
3-50. Determine the force in each cable needed to
support the 17.5-kN platform. Set d = 0.6 m.
17.5 kN
3 m
* 0.6 m
1.2 m
0.9 m
0.9 m
1.2 m
Cartesian Vector Notation :
1.2i – 0.6j – 3k
FAn = FAB
= 0.3578F,µi – 0.2683F,nj – 0.8944F,„k
1.2² + (-0,6)² + (-3)²
0.6i – 0.9j – 3k
FAC = FAc
0.6²
= 0.1881F,ci+ 0.2822F,cj – 0.9407F,k
%3D
F= 17.5 kN
+ 0.9² + (-3)²
0.3 m
-1.2i + 0.3j – 3k
FAD = FAD
= -0.3698Fapi + 0.09245FApj – 0.9245F,Apk
%3D
(-1,2)² + 0.3² + (-3)²
F = {17.5k) kN
1.2 m
3 m
0.9 m
Equations of Equilibrium :
0.9 m
EF = 0; FAn + FẠc+ FAp + F = 0
Fae
(0.3578FAH + 0.1881F,¢ – 0.3698Fµp)i
3 m
+ (-0.2683F,g + 0.2822Fxc + 0.09245FAD)j
+ (-0.8944FAB – 0.9407F¾C – 0.9245FAD + 17.5)k = 0
%3D
Transcribed Image Text:3-50. Determine the force in each cable needed to support the 17.5-kN platform. Set d = 0.6 m. 17.5 kN 3 m * 0.6 m 1.2 m 0.9 m 0.9 m 1.2 m Cartesian Vector Notation : 1.2i – 0.6j – 3k FAn = FAB = 0.3578F,µi – 0.2683F,nj – 0.8944F,„k 1.2² + (-0,6)² + (-3)² 0.6i – 0.9j – 3k FAC = FAc 0.6² = 0.1881F,ci+ 0.2822F,cj – 0.9407F,k %3D F= 17.5 kN + 0.9² + (-3)² 0.3 m -1.2i + 0.3j – 3k FAD = FAD = -0.3698Fapi + 0.09245FApj – 0.9245F,Apk %3D (-1,2)² + 0.3² + (-3)² F = {17.5k) kN 1.2 m 3 m 0.9 m Equations of Equilibrium : 0.9 m EF = 0; FAn + FẠc+ FAp + F = 0 Fae (0.3578FAH + 0.1881F,¢ – 0.3698Fµp)i 3 m + (-0.2683F,g + 0.2822Fxc + 0.09245FAD)j + (-0.8944FAB – 0.9407F¾C – 0.9245FAD + 17.5)k = 0 %3D
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