"Cowboy coffee" is prepared by boiling coarse coffee grounds in water. If 12.5 g sucrose (C12H„0„) is added to 225 g cowboy coffee as it is being prepared, by how much is the vapor pressure above the solution reduced? Assume the solvent, the cowboy coffee, has the same properties as water. The vapor pressure of the solvent at 100 °C is 760.0 Torr. Avp = Torr

Osmotic pressures are often reported in units of atmospheres or mm Hg. The latter impliesthat the height of a column of liquid can be used as a measure of pressure. This is, in fact, thebasis of the torricellian barometer from which the units of “torr” come. The pressure, P, isrelated to the height of the column by:P = ρghwhere ρ is the density of the liquid, g is the acceleration due to gravity and h is the height. Whatwill be the height (in mm) of a column of aqueous solution with a density of 0.9987 g/mL, if theosmotic pressure of the solution at 25 °C is 1.4 mm Hg? The density of mercury at thistemperature is 13.8 g/mL

Ff.94.

1-propanol (n-propanol) and 2-propanol (isopropanol) form ideal solutions in all proportions. Calculate the partial pressure and the mole fraction (y) of the vapor phase of each component in equilibrium with each of the given solutions at 25 °C. Pprop=20.9 Torr and Piso = 45.2 Torr at 25 °C. A solution with a mole fraction of Xprop = 0.238. Pprop= Piso = yprop= Viso = A solution with a mole fraction of Xprop = 0.476. Pprop= Piso = yprop= Viso = A solution with a mole fraction of Xprop = 0.714. Pprop= Piso = yprop= Viso = Torr Torr Torr Torr Torr Torr

The organic compounds chloroform and dichloromethane form ideal solutions when mixed together; at 25 �C the total vapor pressure from a mixture of these two compounds was 345.322 torr. What is the mole fraction of chloroform? Given that the vapor pressure of pure chloroform and pure dichloromethane are 205 torr and 415 torr, respectively, at 25�C.  0.6682    0.4430  0.3318  0.5570