College Physics
11th Edition
ISBN: 9781305952300
Author: Raymond A. Serway, Chris Vuille
Publisher: Cengage Learning
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- Two charges +2 µC and +8 µC are placed along the z axis, with the first charge at the origin (z =0) and the second charge at z = +1 m. Find the magnitude and direction of the net force on a -2 nC charge when placed at the following locations below. Overall Hint Review Section 5.3 Coulomb's Law. Use Coulomb's Law to calculate force due to each of two charges and add them together for the net force, minding the directions. For part (c), you will need to do the vector sum (more below). a. halfway between the two charges: magnitude of force is direction is Select an answer b. on the axis at x = -0.5 m: magnitude of force is is Select an answer c. at the coordinate (x, y) = (1 m, 0.5 m) (half a meter above the +8 µC charge in a direction perpendicular to the line joining the two fixed charges): Hint for (c) This problem is fully 2-dimensional. The charge at x = 1 m exerts force along y direction; the charge at the origin exerts force along the line connecting (x, y) = (0,0) and (z,y) = (1…arrow_forwardTwo charges +4 µC and +11 µC are placed along the x axis, with the first charge at the origin (x = 0) and the second charge at x = +1 m. Find the magnitude and direction of the net force on a -9 nC charge when placed at the following locations below. Overall Hint Review Section 5.3 Coulomb's Law. Use Coulomb's Law to calculate force due to each of two charges and add them together for the net force, minding the directions. For part (c), you will need to do the vector sum (more below). a. halfway between the two charges: magnitude of force is direction is Select an answer b. on the x axis at x = -0.5 m: magnitude of force is direction is Select an answer c. at the coordinate (x, y) = (1 m, 0.5 m) (half a meter above the +11 µC charge in a direction perpendicular to the line joining the two fixed charges): Hint for (c) Magnitude of force is degrees below -x axis. mN, and the direction is mN, and the mN, and thearrow_forwardbeen stuck on this question for a while, would appreciate help If a particulate, with a mass of 2.1 x 10-5 kg, acquires a charge of 3.2 μC , the electrical force on the particulate, due to the electric field is: a 4.3 x 10-2 N b 4.3 N c 4.3 x 106 N d 4.2 x 1011 N explanation would be highly appreciated!arrow_forward
- The electrostatic force acting between a pair of charges 1 separated by 1.2 m is reduced to its original value by 14 increasing the separation distance. What is the new separation distance between the charges? distance = marrow_forwardQ2 R If the distance R between the two charges Q1 and Q2 is reduced to one-third of what it was, the force between them a doubles O b also becomes one-third increases by a factor of 9 O d decreases by a factor of 9 triplesarrow_forwardAn alpha particle (charge 2e) is sent at high speed toward a gold nucleus (charge 79e). What is the electric force acting on the alpha particle when it is 3.5 x 10-14 m from the gold nucleus? Group of answer choices 36.80 N towards 29.72 N towards 36.80 N away 29.72 N awayarrow_forward
- 3 and 4arrow_forwardwhat is the force between two point charges that are 0.01 meters apart and each has a positive charge of 3 x 10^-6 Coulombs? The Coulomb constant k = 9x 10^9 N x m^2 / C^2arrow_forwardwhat is the force between two point charges that are 0.02 meters apart and each has a positive charge of 4x10^-6 coulombs? The coulomb constant k =9 x 10^9 N•m^2 /C^2arrow_forward
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