Convert the following into Pep/9 assembly language: #include using namespace std; int num int main() { cin >> num; num = num % 16; cout << "num=" << num << endl; return 0; } Hint for the %16 part: 0 % 16 = 0 1 % 16 = 1 2 % 16 = 2 ... 14 % 16 = 14 15 % 16 = 15 16 % 16 = 0 17 % 16 = 1 ... 30 % 16 = 14 31 % 16 = 15 32 % 16 = 0 ... Convert all the results to binary. What do they all have in common?
Convert the following into Pep/9 assembly language: #include using namespace std; int num int main() { cin >> num; num = num % 16; cout << "num=" << num << endl; return 0; } Hint for the %16 part: 0 % 16 = 0 1 % 16 = 1 2 % 16 = 2 ... 14 % 16 = 14 15 % 16 = 15 16 % 16 = 0 17 % 16 = 1 ... 30 % 16 = 14 31 % 16 = 15 32 % 16 = 0 ... Convert all the results to binary. What do they all have in common?
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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Question
Convert the following into Pep/9 assembly language:
#include <iostream>
using namespace std;
int num
int main() {
cin >> num;
num = num % 16;
cout << "num=" << num << endl;
return 0;
}
Hint for the %16 part:
0 % 16 = 0
1 % 16 = 1
2 % 16 = 2
...
14 % 16 = 14
15 % 16 = 15
16 % 16 = 0
17 % 16 = 1
...
30 % 16 = 14
31 % 16 = 15
32 % 16 = 0
...
Convert all the results to binary. What do they all have in common?
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