Construt a 90% confidence interval of the population proportion using the given information . ×=40, n=200 The lower bound is? The supper bound is?

= 1 = 2 F3 Lower limit: Upper limit: 4 In a sample of 200 college seniors, 160 responded positively when asked if they have spring fever. Based upon this, compute a 90% confidence interval for the proportion of all college seniors who have spring fever. Then find the lower limit and upper limit of the 90% confidence interval. Carry your intermediate computations to at least three decimal places. Round your answers to two decimal places. (If necessary, consult a list of formulas.) X Ś

Construct a confidence interval of the population proportion at the given level of confidence. x = 860, n = 1100, 94% confidence The lower bound of the confidence interval is (Round to the nearest thousandth as needed.) The upper bound of the confidence interval is (Round to the nearest thousandth as needed.)

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If n=520 and ˆpp^ (p-hat) = 0.4, construct a 98% Confidence Interval.In order to use technology, you need to compute the number of successes:x = n*ˆpp^Give your answers to three decimals. ________< p < __________

When finding the upper bound, UU, of a confidence interval given the lower bound, LL, and the margin of error, EE, we use the formula U=L+2EU=L+2E. Find the upper bound for the proportion of babies that are born preterm if the lower bound is L=0.364L=0.364 and the margin of error is E=0.176E=0.176. Round your answer to 3 decimal places.U=

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Find the left and right chi square values, then give the confidence interval. Sample Variance s 15.99 %3D Confidence Level c = 0.90 and Sample Size n = 13 and x %3D %3D At the 90 % level of confidence the population variance is between and (Round all answers to 3 decimal places)

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Actually 25