In a sample of 200 college seniors, 160 responded positively when asked if they have spring fever. Based upon this, compute a 90% confidence interval for the proportion of all college seniors who have spring fever. Then find the lower limit and upper limit of the 90% confidence interval. Carry your intermediate computations to at least three decimal places. Round your answers to two decimal places. (If necessary, consult a list of formulas.) Lower limit: Upper limit:

A statistics practitioner took a random sample of 49 observations from a population and computed the sample mean to be 100. For each confidence interval, enter your answer in the form (LCL, UCL). You must include the parentheses and the comma between the confidence limits.   A. Suppose the population standard deviation is 28. Estimate the population mean with 95% confidence. Confidence Interval =  B. Suppose the population standard deviation is 41. Estimate the population mean with 95% confidence. Confidence Interval =  C. Suppose the population standard deviation is 10. Estimate the population mean with 95% confidence. Confidence Interval =

#11 In a recent poll, 310 people were asked if they liked dogs, and 95% said they did. Find the Margin of Error for this poll, at the 90% confidence level. Give your answer to four decimal places if possible. =

A poll of 2368 U.S. adults found that 40% regularly used Facebook as a news source. Find the margin of error and confidence interval for the percentage of U.S. adults who regularly use Facebook as a news source, at the 90% level of confidence. Round all answers to 2 decimal places. Margin of Error (as a percentage): Confidence Interval: % to % Find the margin of error and confidence interval for the percentage of U.S. adults who regularly use Facebook as a news source, at the 95% level of confidence. Round all answers to 2 decimal places. Margin of Error (as a percentage): Confidence Interval: % to % Find the margin of error and confidence interval for the percentage of U.S. adults who regularly use Facebook as a news source, at the 99% level of confidence. Round all answers to 2 decimal places. Margin of Error (as a percentage): Confidence Interval: % to % The more error we allow, the less precise our estimate. Therefore, as the confidence level increases, the precision of our…

If n = 15, ¯xx¯ = 36, and s = 12, construct a confidence interval at a 90% confidence level. Assume the data came from a normally distributed population. Give your answers to three decimal places.

Out of 400 people sampled, 224 had children under the age of 18. Based on this, construct a 90% confidence interval for the true population proportion of people with children under the age of 18.Give your answers as decimals, to three places.________< p <________

Tina catches a 14-pound bass.  She does not know the population mean or standard deviation.  So she takes a sample of five friends and they say the last bass they caught was 9, 12, 13, 10, and 10 pounds.  Find the t and calculate a 95% (α = .05) confidence interval.

If n=17, (x-bar)=48, and s=2, construct a confidence interval at a 80% confidence level. Assume the data came from a normally distributed population. Give your answers to one decimal place.

A poll of 2338 U.S. adults found that 71% regularly used Facebook as a news source. Find the margin of error and confidence interval for the percentage of U.S. adults who regularly use Facebook as a news source, at the 90% level of confidence. Round all answers to 2 decimal places. Margin of Error (as a percentage): Confidence Interval: % to % Find the margin of error and confidence interval for the percentage of U.S. adults who regularly use Facebook as a news source, at the 95% level of confidence. Round all answers to 2 decimal places. Margin of Error (as a percentage): Confidence Interval: % to %

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