**Normal Probability Plot Construction for Coating Thickness**In this exercise, we aim to construct a normal probability plot for a sample of observations regarding the coating thickness of low-viscosity paint. The sample observations are as follows:- 0.81, 0.86, 0.88, 1.03, 1.08, 1.13, 1.29, 1.29- 1.47, 1.50, 1.59, 1.60, 1.64, 1.73, 1.74, 1.81**Step-by-Step Instruction:**1. **Using the SALT Tool:** - Click the "USE SALT" button to assist in constructing the normal probability plot.2. **Determine Z Percentiles:** - You need to determine the z percentile associated with each sample observation. Enter your answers rounded to two decimal places. - The sample observation of 0.81 has been associated with a z percentile of 0.05, but this is marked as incorrect, indicating a check is needed.3. **Data Observations and Z Percentiles:** The observations are grouped as shown below: - First group: 0.81, 0.86, 0.88, 1.03, 1.08, 1.13, 1.29, 1.29 - Second group: 1.47, 1.50, 1.59, 1.60, 1.64, 1.73, 1.74, 1.814. **Select the Appropriate Plot:** - Determine which plot best represents the normal probability plot for this sample of observations using the given data.This exercise enhances understanding of the relationship between the sample data and the normal distribution by utilizing the normal probability plot. Adjust your calculations for z percentiles and interpret the plots accordingly for an accurate analysis.

Given is the data on 16 observations.We have to find the z-percentile for each observation.Find we…

Answered: Construct a normal probability plot for…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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The accompanying data is on cube compressive strength (MPa) of concrete specimens. 112.4 97.0 92.7 86.0 102.0 99.3 95.8 103.5 89.0 86.7 A USE SALT (a) Is it plausible that the compressive strength for this type of concrete is normally distributed? O The normal probability plot is not acceptably linear, suggesting that a normal population distribution is not plausible. O The normal probability plot is not acceptably linear, suggesting that a normal population distribution is plausible. O The normal probability plot is acceptably linear, suggesting that a normal population distribution is not plausible. O The normal probability plot is acceptably linear, suggesting that a normal population distribution is plausible. (b) Suppose the concrete will be used for a particular application unless there is strong evidence that true average strength is less than 100 MPa. Should the concrete be used? Carry out a test of appropriate hypotheses. State the appropriate hypotheses. O Hoi u= 100 Hai u>…
b. Sketch a standard normal curve and shade the area under the curve that lies between - 3 and - 2.1. Choose the correct graph below. А. В. С. OD. - 2.1 2.1 O 2.1 3 O 2.1 3 The area that lies between - 3 and - 2.1 is 0.98 (Round to four decimal places as needed.) N
(3.) A system contains components connected in parallel as shown in the diagram. If all components operate inderentently, & each component has probability 0.45 of failing What is the minimum number of components that must be connected in parallel so that th Probability that the system operateds exceeds 0.9999? The minimun number of components that must be connected in parallel is.
Construct a normal probability plot for the following sample of observations on coating thickness for low-viscosity paint. 0.85 0.86 0.86 1.02 1.10 1.11 1.31 1.31 1.47 1.48 1.57 1.63 1.64 1.73 1.77 1.84 USE SALT Determine the z percentile associated with each sample observation. (Round your answers to two decimal places.) Sample observation 0.85 0.86 1.11 z percentile Sample observation z percentile 1.47 1.48 0.86 1.57 1.02 1.63 1.10 1.64 1.73 1.31 1.77 1.31 1.84
Total plasma volume is important in determining the required plasma component in blood replacement therapy for a person undergoing surgery. Plasma volume is influenced by the overall health and physical activity of an individual. Suppose that a random sample of 50 male firefighters are tested and that they have a plasma volume sample mean of x = 37.5 ml/kg (milliliters plasma per kilogram body weight). Assume that ? = 7.20 ml/kg for the distribution of blood plasma.
Consider the following sample of observations on coating thickness for low-viscosity paint: 0.83 0.88 0.88 1.04 1.09 1.12 1.29 1.31 1.48 1.49 1.59 1.62 1.65 1.71 1.76 1.83 Assume that the distribution is normal. A. Calculate a point estimate of the mean value of coating thickness B. Estimate P[X < 1.5], the proportion of all thickness values less than 1.5. (Hint: Estimate u and o first) C. What is the estimated standard error used in the first question? Ans. A. 1.3481 B. 0.6736 C. 0.0846
Which way of dispensing champagne, the traditional vertical method or a tilted beer-like pour, preserves more of the tiny gas bubbles that improve flavor and aroma? The following data was reported in an article. Type of Pour n Mean (g/L) SD 0.6 Traditional 4 Slanted Traditional 4 0.4 0.2 Slanted 4 0.1 Assume that the sampled distributions are normal. Temp (°C) 18 18 12 12 LUSE SALT (a) Carry out a test at significance level 0.01 to decide whether true average CO₂, loss at 18°C for the traditional pour differs from that for the slanted pour. (Use μ, for the traditional pour and State the relevant hypotheses. OH₂H₂H₂ 0 OHH₁-H₂0 H₂H₁-H₂=0 OH₂H₁ H₂=0 H₂H₁ H₂ <0 (b) Repeat the test of hypotheses suggested in (a) for the 12° temperature. Is the conclusion different from that for the 18° temperature? Note: The 12° result was reported in the popular media. (Use u, for the traditional pour and for the slanted pour.) State the relevant hypotheses. OHH, H₂ <0 H₂₁₂4₁₂4₂₁₂=0 - OH₂H₁-H₂=0 H₂H₂H₂ #0…
ge=19 Choose the best option for the standard normal curve such that Z = 1.5 and z = 2.5. Select one: a. 0.0606 O b.0.0668 O c. 0.4332 O d. 0.4938
Test for Potassium (Normal Value: 3.5-5.5 mmol/L) Day Result 1 3.5 3.6 3 4.5 4 3.6 5 4.9 4.5 7 3.8 Mean Standard Deviation Coefficient of Variation
Construct a normal probability plot for the following sample of observations on coating thickness for low-viscosity paint. 0.82 0.87 0.90 1.02 1.11 1.14 1.31 1.33 1.47 1.48 1.61 1.63 1.64 1.72 1.74 1.84 Determine the z percentile associated with each sample observation. (Round your answers to two decimal places.) Sample observation 0.82 0.87 0.90 1.02 1.11 1.14 1.31 1.33 z percentile Sample observation 1.47 1.48 1.61 1.63 1.64 1.72 1.74 1.84 z percentile
Consider the following sample of observations on coating thickness for low-viscosity paint. 0.83 0.88 0.88 1.03 1.09 1.21 1.29 1.31 1.42 1.49 1.59 1.62 1.65 1.71 1.76 1.83 Assume that the distribution of coating thickness is normal (a normal probability plot strongly supports this assumption). (c) Calculate a point estimate of the value that separates the largest 10% of all values in the thickness distribution from the remaining 90%. [Hint: Express what you are trying to estimate in terms of μ and σ.] (Round your answer to four decimal places.) (d) Estimate P(X < 1.2), i.e., the proportion of all thickness values less than 1.2. [Hint: If you knew the values of μ and σ, you could calculate this probability. These values are not available, but they can be estimated.] (Round your answer to four decimal places.) (e) What is the estimated standard error of the estimator that you used in part (b)? (Round your answer to four decimal places.)
A population data set with a normal distribution has a mean u = 4 and a standard deviation o = 1.1. Find the approximate proportion of observations in the data set that lie below 5.1? O 0.84 0.17 O 0.34 0.68

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