consider you are looking at a virtual memory of size 1 GiB also a physical memory of size 128 KiB and a page size equal to 8 KiB. FIgure out how many bits are used to specify a virtual page number?

Consider a logical address space of 256 pages with a 4-KB page size, mapped onto a physical memory of 64 frames. (book: 8.23) How many bits are required in the logical address? How many bits are required in the physical address?

Registers in RISC-V are 64-bit.  For the sake of simplicity, consider the following instructions operating on 32-bit registers.  Assume that registers x5 and x6 hold the values 0xBBBBBBBB and 0x00000000, respectively. What is the value in x6 for the followingslli x6, x5, 6 Using the result from the part above, what is the value in x6 for the following instruction.            srli x6, x6, 6

Suppose a computer system uses 16-bit addresses for both its virtual and physical addresses. In addition, assume each page (and frame) has size 256 bytes. How many bits are used for the page number? How many bits are used for the offset? 8 bits each. With this system, what’s the maximum number of pages that a process can have? 256 Suppose that each entry in the page table comprises 4 bytes (including the frame number, the valid bit, and miscellaneous “bookkeeping bits”). An OS uses an array to store the page table. What is the size of the page table? 1024 Bytes Furthermore, suppose the first 6 pages of a process map to frames 222 to 227 (as decimal numbers), and the last 5 pages of the process map to frames 1 to 5 (also decimal numbers). All other pages are invalid. Draw the page table, including the valid bit and the frame number. DONE Translate the following virtual addresses to physical addresses, and show how you obtain the answers. (Hint: You do not need to convert…