Consider the system shown in Fig. P1-77. If a change of 0.7 kPa in the pressure of air causes the brine-mercury interface in the right column to drop by 5 mm in the brine level in the right column while the pressure in the brine pipe remains constant, determine the ratio of A, /A₁. Air Area, A₁ Water Mercury SG 13.56 Brinc pipe SG 1.1, Area, Az

Consider the system shown in Fig. P1-77. If a change of 0.7 kPa in the pressure of air causes the brine-mercury interface in the right column to drop by 5 mm in the brine level in the right column while the pressure in the brine pipe remains constant, determine the ratio of A, /A₁. Air Area, A₁ Water Mercury SG 13.56 Brinc pipe SG 1.1, Area, Az

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

See similar textbooks

Similar questions

The right limb of a simple U-tube manometer containing mercury is open to the atmosphere while the left limb is connected to a pipe in which a fluid of SG = 0.9 is flowing. The center of the pipe is 12 cm below the level of mercury in the right limb. Find the pressure of fluid in the pipe if the difference of mercury level in the two limbs is 20 cm. Use SGHg = 13.6. P A 12 I 21K 20 cm
- Consider the system shown in the figure. If a change of P kPa in the pressure of air causes the brine- mercury interface in the right column to drop by d mm in the brine level in the right column while the pressure in the brine pipe remains constant, determine the ratio of A2/A1. Air Brine pipe SG = 1.1 Water Area, Aj Р (КРа) | d (mm) 35 Area, A2 Mercury SG = 13.56 7
w . ie P1 Asimple U-lube manometer Containg Mere is connecled to apipe in which afiuid se Pgr =d g and having vacum Pressure 12 Flowing the otherend of manomela 1S O Pen to atmos Phere • Find the vacum Aressum in Pipe-if difference of mercury level in the two limbs i30cm and the height of Fiuid in the Jeft from the Center of Pipe is 16 cm belu 30 A
Methanol (SG=0.792) is contained in a large tank under a pressure of 350000 Pa absolute. When a valve on the bottom of the tank is opened, the methanol drains freely though a 0.02 m ID tube whose outlet is 7.00 m below the surface of the methanol. The pressure at the outlet of the discharge pipe is 101325 Pa. Some useful constants and conversions: g = 9.8 m/s2 , Pref = 1000 kg/m3 . a. Draw the system. Label points I and 2 (where you will define A= 2-1) and label the variables with values b Write the general form of the energy balance. Cancel out negligible terms, and state the keyword/assumption to justify. Simplify to the resultant energy balance. c.) Assume the diameter of the tank is very big compared to the drain tube velocity, which make the velocity of liquid in the tank equal to zero. Estimate the methanol discharge velocity in the drain tube in m/s. *hint: divide your EB by m to eliminate m and V. Recall, n = pV = pvA and = v/m=1/p
Consider the system shown below. If a change of 0.7 kPa in the pressure of air causes the brine-mercury interface in the right column to drop by 5 mm in the brine level in the right column while the pressure in the brine pipe remains constant, determine the ratio of A2/A1. Brine pipe SG= 1.1 Air Water Mercury SG = 13.56 Area, A₁ Area, A₂
B) A closed cylindrical tank filled with water has a hemispherical dome and is connected to an inverted piping system as shown in Fig.(2). The liquid in the top part of the piping system has a relative density of 0.8, and the remaining parts of the system are filled with water. If the pressure gage reading at A is 60 kPa, determine: (a) the pressure in pipe B, and (b) the pressure head, in millimeters of mercury, at the top of the dome lpoint C2. Hemispherical dome SG = 0.8 4 m PA= 60 kPa 3 m 3 m Water 2 m Water
. Ooredoo 9:02 PM moodle.nct.edu.om - Private A simple U tube manometer is used to measure the pressure of oil flowing in a pipeline. Its left limb is open to the atmosphere and the right limb is connected to the pipe. The center of the pipe is 170 mm below the level of mercury in the left limb. If the difference of mercury level in the two limbs is 240 mm, determine the gauge pressure of the oil in the pipe in Pascal. The specific gravity of the oil & mercury is 1.86 and 13.6 respectively. Solution: (i) Density of oil in kg/m³ 66% (ii) Density of mercury in kg/m³ (iii) Height of the Oil in the right limb (in meters of oil) h₁ (iv) The gauge pressure of the oil in the pipe in (in Pascal)
The level of mercury in the right limb is 0.6m above that in the left limb and the space above mercury in the rightlimb contains benzene (SG=0.88) to a height of 0.4m. The left limb of a U-tube manometer is connected to a pipe conveying water, the level of mercury (SG=13.6) in the leg being 0.8m below the center of the pipeline and the right limb is open to atmosphere. Determine the pressure ofwater in the pipe.
Vapor pressure measurements at several different temperatures are shown below for mercury. Determine deta Hvap. T= 200 and 250 degrees Celsius P= 17.3 and 74.4(mm Hg)
fluid is prevented from moving to the top of the tank. Use unit weight of water = 9.79 kN/m³. (a) Determine the pressure pA in kPa, (b) the value of h in small open cylindrical tank containing cleaning fluid (s.g. = 0.8) at a height h. The pressure PB = 13.4 kPa gage and pc = 13.42 kPa gage. Assume the cleaning Problem 2- 52 lindrical tank contains water at a height of 55 mm, as shown. Inside is a %3D %3D and (c) the value of y in millimeters. mm, Ans: (a) 12.88; (b) 10.2; (c) 101 PA Air Water 55 mm Kerosene HD PB Pc Mercury (s.g. = 13.6)
Consider the system shown in the figure. If a change of 0.75 kPa in the pressure of air causes the brine-mercury interface in the right column to drop by 5 mm in the brine level in the right column while the pressure in the brine pipe remains constant, determine the ratio of A2/A1. Brine Air pipe SG=1.1 RS Water Area, A₂ Mercury SG= 13.56 Area, A₁ The ratio of A2/A1 is
When measuring small pressure differences with a manometer, one arm of the manometer may be inclined to improve the accuracy of the reading. (The pressure difference is still proportional to the vertical distance and not the actual length of ghr fluid along the tube.) The air pressure in a circular duct is to be measured using a manometer whose open arm is inclined 25 degrees from horizontal. The density of the fluid in the manometer is 900 kg/m³, and the vertical distance between the fluid levels in the two arms of the manometer is 7.8 inches. Determine the gauge pressure of the air in the duct and the length of the fluid column in the inclined arm above the fluid level in the vertical arm.