Consider the reversible reaction 2A 2 B which is second-order in the forward direction and first-order in the reverse direction. Write the rate law for the reaction, and integrate it to obtain an expression for the concentration of A as a function of time. The concentrations at 1 = 0 are [A] = A,, [B] = 0.

13) The following gas-phase complex reactions follow elementary rate laws A+ 2B-C 2A+ C D RB=WBa=k'C(CB-CBS)α = KCB CB and take place isothermally in an isothermal membrane reactor. An equal molar feed of A and B enter the reactor, and species C is able to diffuse through the membrane. Pressure drop is significant in the reactor. Set up the equations that you would need to plot and analyze the molar flow rates of each species and conversion of species A as a function of volume. Include all equations that you would need to enter into Polymath except for explicit equations defining constants (i.e., vo = 1 L/min, etc.) or initial and final conditions. A species: A,B,C,D MB: =rA dFA dFB=B dFc CFD =rc-RC V dv dv CH =rD Rate laws: -VA=KACACB -VA = KACACC N Net Rate laws: rj = Σ Relative Rates: VA=VB = C=D Fj olchiometry: C = CTo FP7 = C=C TO + T=FA+FB+FC+FD FT PO FJ =Cj=CTO! FT isothermal essure Drop: d (P/Po) - dy -- a T FT Ap dw dw Hold this for each specie 2y 24 TO FTO X=> RC = 7

can you please help with anything?  1) Calculate the mole flow rates of all components in stream. 2) Calculate the single pass conversion 3) overall conversion

note: please show all the necessary steps/solutions. do not round off in between solutions. correct answers pls. type the answers. thank you..