Consider the reversible dissolution of lead(II) chloride. PBC12 (s) Pb† (aq) + 2 C1¯ (aq) 2+ Suppose you add 0.2478 g of PbCl2 (s) to 50.0 mL of water. When the solution reaches equilibrium, you find that the concentration of pb²+ (aq) is 0.0159 M and the concentration of Cl¯ (aq) is 0.0318 M. What is the value of the equilibrium constant, Kc, for the dissolution of PBC12 ? Type answer:

At 25 °C, an aqueous solution has an equilibrium concentration of 0.00217 M for a generic cation, A+(aq), and 0.00109 M for a generic anion, B2−(aq). What is the equilibrium constant, ?sp, of the generic salt A2B(s)?

a) Balance the following equation and write it below: Fe (s) + Mg3(PO,), (aq) → Fe;(P 0,), (aq) + Mg(s) b) If you added 134.2 grams of Iron to an excess of Mg,(PO,)2, how many moles of Iron have you added? c) Assuming the reaction is reversible, in which direction would the equilibrium shift if Fe was removed from the solution (left, right, or no change?) d) What type of reaction is this?

Chapter 12 part 1 #12

Write the mathematical expression for the equilibrium constant and using concentrations < 1 M, makeup two sets of concentrations that describles a mixture of A,B, and C at equilibrium.

8. You mix a 200.0-mL sample of a solution that is 1.5 X 10-³ M in Cu(NO3)2 with a 250.0-mL sample of a solution that is 0.20 M in NH3. After the solution reaches equilibrium, what concentration of Cu²+ (aq) remains? For [Cu(NH3)4]²+, Kf = 1.7 x 1013 me that

6. Give the equilibrium constant for the following reaction. 2PB1, (g) + 3Cl,(s) 2PCI;(g) + 3Br,(g)

The equilibrium constant of the reaction 2C02 = 2C0+02 is 1.08. If the concentrations of CO and O2 is 0.86 M and 0.54 M, respectively, what is the concentration of carbon dioxide?

A student determines that an aqueous solution that contains 0.474 M potassium hypochlorite and 0.180 M hypochlorous acid, also has an H30* concentration of 1.89x10-8 M. Based on these data, calculate the value of the equilibrium constant K for the equilibrium: HCIO(aq) + H2O =H30*(aq) + ClO(aq) Calculate K as is usually done, omitting the solvent, water, from the expression for K: K