Consider the reaction: 2NO(g) + 02(g) → 2NO2(g) Suppose that a particular moment during the reaction nitric oxide (NO) is reacting at a rate of-0.010 M/s (with the rate expressed as a negative number since NO is a reactant). At what rate is molecular oxygen reacting?

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Chapter1: Chemical Foundations
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Consider the reaction:

\[ 2\text{NO}(g) + \text{O}_2(g) \rightarrow 2\text{NO}_2(g) \]

Suppose that at a particular moment during the reaction, nitric oxide (NO) is reacting at a rate of \(-0.010 \, \text{M/s}\) (with the rate expressed as a negative number since NO is a reactant). At what rate is molecular oxygen reacting?

\[ \boxed{\phantom{M}} \, \frac{M}{s} \]

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**Note for educational websites**: In this problem, you are tasked to determine the rate at which molecular oxygen (\(\text{O}_2\)) is reacting. Given that the rate of consumption of \(\text{NO}\) is twice the rate of consumption of \(\text{O}_2\), and knowing the stoichiometry of the reaction, you can derive the rate of \(\text{O}_2\) consumption.
Transcribed Image Text:--- **Enter your answer in the provided box.** Consider the reaction: \[ 2\text{NO}(g) + \text{O}_2(g) \rightarrow 2\text{NO}_2(g) \] Suppose that at a particular moment during the reaction, nitric oxide (NO) is reacting at a rate of \(-0.010 \, \text{M/s}\) (with the rate expressed as a negative number since NO is a reactant). At what rate is molecular oxygen reacting? \[ \boxed{\phantom{M}} \, \frac{M}{s} \] --- **Note for educational websites**: In this problem, you are tasked to determine the rate at which molecular oxygen (\(\text{O}_2\)) is reacting. Given that the rate of consumption of \(\text{NO}\) is twice the rate of consumption of \(\text{O}_2\), and knowing the stoichiometry of the reaction, you can derive the rate of \(\text{O}_2\) consumption.
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