Consider the mass spectrometer shown schematically in Figure P19.36. The electric field between the plates of the velocity selector is 950 V/m, and the magnetic fields in both the velocity selector and the deflection chamber have magnitudes of 0.930 T. Calculate the radius of the path in the system for a singly charged ion with mass m = 2.18 × 10−26 kg. Hint: See Problem 35.

Particles with one electron removed are fired through a velocity selector and emerge with a velocity of 354 m/s. The particles then enter a mass spectrometer, which has a magnetic field strength of 7.90x10-3 T and hit a detection screen in a semi-circular arc with a diameter of 21.0 cm Part A Calculate the mass of the particles. Hνα ΑΣφ ? kg m = Submit Request Answer Part B The magnetic field in the velocity selector will be O to the left O out of the page O into the page O to the right 0 0 0 0 0 O O /o o о о о о

A carbon-14 ion with a charge of +6.408x10^-19 C and a mass of 2.34x10^-26 kg is sent through a mass spectrometer and hits a detector at a point 10.0 cm to the left of  where the beam leaves the velocity selector. The velocity selector and the detector are both in a region of magentic field of strength 0.500 T.    What is the direction of the magnetic field and what is the speed of the particle after it leaves the velocity selector?    Please also explain and show the steps you used to get there/the physics behind why/how you got to the answer to help me better understand. Thank you soo much. Also, the work and the explanation or most important because I already have the correct answer - I'm just unsure of how to get there.

In a Bainbridge mass spectrometer (Figure 1), ions pass through the electromagnetic field of a velocity selector and are then deflected by a magnetic field. Knowing that E​ = 3.1  × 105 V/m and that ​B1 = B2 = ​0.32  T, calculate the difference of the positions on the photographic plate for the ions of charge q​ = e of the nitrogen isotopes of masses 14 u and 15 u. Note that 1 u = 1.661 × 10-27 kg.

A carbon-14 ion with a charge of +6.408x10^-19 C and a mass of 2.34x10^-26 kg is sent through a mass spectrometer and hits a detector at a point 10.0 cm to the left of where the beam leaves the velocity selector. The velocity selector and the detector are both in a region of magnetic field of strength 0.500 T. What are the magnitude and direction of the electric field in the velocity selector where the particles travel in a straight line for 15.0 cm? Please also explain and show the steps you used to get there/the physics behind why/how you got to the answer to help me better understand. Thank you soo much. Also, the work and the explanation or most important because I already have the correct answer - I'm just unsure of how to get there.

An alpha particle (He++) is passing horizontally over your paper from right to left at 7.73 x 10^6 m/s when a large, uniform magnetic field of 12.44 T out of the paper is immediately turned on. The ion is caught in a circular path. An accurate and detailed sketch of the ion, magnetic field, and path of the ion is recommended

A mixture contains two types of particles, 40K and an unknown substance, X. 4°K has a mass of 6.64x10-26 kg but the mass of substance X is not known. The charge on both substances is the same but also unknown. The particles are launched into the mass spectrometer at a speed of 6750 m/s. The mass spectrometer has a 7.47x103 T magnetic field pointing out of the page (as shown below). The 4°K particles hit a semi-circular detector with a diameter of 25.0 cm and substance X hits the detector with diameter of 28.0 cm Path of °K ions Velocity selector Path of substance X ions Mass Spectrometer Magnetic Field out of page Part A The charge on the particles is: q = 4,80x10-19 C Submit Previous Answers v Correct Part B How many electrons were removed from 4°K and substance X? ? Ne = Submit Request Answer Part C What is the mass of substance X? mx = kg

A 8.00-cm-long wire is pulled along a U-shaped conducting rail in a perpendicular magnetic field. The total resistance of the wire and rail is 0.340 2. Pulling the wire at a steady speed of v= 4.00 m/s causes 4.30 W of power to be dissipated in the circuit. /myct/itemView?assignmentProblemID=195605... 34² F2 A 3 E D 80 F3 $ 4 R F a F4 V % L 5 T 0 F5 A 6 B Part A How big is the pulling force? Express your answer with the appropriate units. ► View Available Hint(s) F= Part B Y Submit FO Submit Provide Feedback B = Value What is the strength of the magnetic field? Express your answer with the appropriate units. ► View Available Hint(s) H Value & 7 μÀ μÅ ← F7 N U 3 8 J C FO ? Units Units DII FB 1 M PwC ? 10. 9 K D F9 O 30 a F10 L P 4 F11 + F12

An electron in a TV CRT moves with a speed of 5.5 × 107 m/s, in a direction perpendicular to the Earth’s magnetic field, which has a strength of 5.75 × 10-5 T. Part (a)  What electric field strength in kV/m must be applied perpendicular to the Earth’s magnetic field to make the electron moves in a straight line?  Part (b)  If this is done between plates separated by 1.1 cm, what is the voltage applied in V? (Note that TVs are usually surrounded by a ferromagnetic material to shield against external magnetic fields and avoid the need for such a correction.)

can you please ans (a) (b) (c)?