Consider the hypothesis statement to the right using a=0.10 and the data to the right from two independent samples. Họi H -H250 Hi H-H2 >0 X, = 88 o, = 24 n = 45 a) Calculate the appropriate test statistic and interpret the result. b) Calculate the p-value and interpret the result. Click hero to view page 1 of the standard normal table, Click here to viow page 2 of the standard normal table, * = 77 02 = 18 ng = 55 a) The test statistic is 2.54 (Round to two decimal places as needed.) Determine the appropriate critical value(s). The critical value(s) is(are) 1.28. (Round to two decimal places as needed. Use a comma to separate answers as needed.) Since the test statistic falls in the rejection region, reject Ho. There is sufficient evidence to conclude that the mean of population 1 is greater than the mean of population 2. b) The p-value is (Round to three decimal places as needed.)
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- A 0.05 significance level is used for a hypothesis test of the claim that when parents use a particular method of gender selection, the proportion of baby girls is different from 0.5. Assume that sample data consists of 66 girls in 144 births, so the sample statistic of 1124 results in a z score that is 1 standard deviation below 0. Complete parts (a) through (h) below.Click here to view page 1 of the Normal table. LOADING... Click here to view page 2 of the Normal table. LOADING...Question content area bottomPart 1a. Identify the null hypothesis and the alternative hypothesis. Choose the correct answer below.A.H0: p=0.5H1: p>0.5B.H0: p≠0.5H1: p=0.5C.H0: p=0.5H1: p≠0.5D.H0: p=0.5H1: p<0.5Part 2b. What is the value of α?α=0.050.05 (Type an integer or a decimal.)Part 3c. What is the sampling distribution of the sample statistic? Student (t) distribution Normal distribution χ2Part 4d. Is the test two-tailed, left-tailed, or right-tailed? Left-tailed Two-tailed…A 0.05 significance level is used for a hypothesis test of the claim that when parents use a particular method of gender selection, the proportion of baby girls is greater than 0.5. Assume that sample data consists of 78 girls in 144 births, so the sample statistic of 1324 results in a z score that is 1 standard deviation above 0. Complete parts (a) through (h) below.Click here to view page 1 of the Normal table. LOADING... Click here to view page 2 of the Normal table. LOADING...Question content area bottomPart 1a. Identify the null hypothesis and the alternative hypothesis. Choose the correct answer below.Part 7g. What are the critical value(s)?The critical value(s) is/are enter your response here. (Round to two decimal places as needed. Use a comma to separate answers as needed.)Part 8h. What is the area of the critical region?The area is enter your response here. (Round to two decimal places as needed.)I need a clear answer by hand, not by keyboard | dybala
- A study was done using a treatment group and a placebo group. The results are shown in the table. Assume that the two samples are independent simple random samples selected from normally distributed populations, and do not assume that the population standard deviations are equal. Complete parts (a) and (b) below. Use a 0.10 significance level for both parts Treatment Placebo μ μ1 μ2 n 28 32 x 2.35 2.61 s 0.95 0.66 What is the null and alternative hypotheses? The test statistic, t, is? The P-value is? Construct a confidence interval suitable for testing the claim that the two samples are from populations with the same mean. ?<μ1−μ2<?Use the attached image to answer the question: Use the data above to construct a bivariate table and explore if there is an association between one’s education and attitudes toward cohabitation. Is there an association? Describe the pattern of association. Assuming that this is a random sample, test a hypothesis (use α = 0.01) that there is an association between one’s education and attitudes toward cohabitation in the population. Show all your work (state the hypotheses, find the critical value, compute the test statistics, state a conclusion) and write one sentence summarizing the results. (Extra-credit: find the p-value). Is this association weak, moderate or strong? Compute and interpret the appropriate statistic.Data on the weights (Ib) of the contents of cans of diet soda versus the contents of cans of the regular version of the soda is summarized to the right. Assume that the two samples are independent simple random samples selected from normally distributed populations, and do not assume that the population standard deviations are equal. Complete parts (a) and (b) below. Use a 0.05 significance level for both parts. Diet Regular H2 40 40 0.78244 lb 0.81852 lb 0.00435 lb 0.00752 lb a. Test the claim that the contents of cans of diet soda have weights with a mean that is less than the mean for the regular soda. What are the null and alternative hypotheses? B. Ho: H1 H2 O A. Ho: H1=42 H: P1A 0.01 significance level is used for a hypothesis test of the claim that when parents use a particular method of gender selection, the proportion of baby girls is different from 0.5. Assume that sample data consists of 55 girls in 100 births, so the sample statistic of 1120 results in a z score that is 1 standard deviation above 0. Complete parts (a) through (h) below.Click here to view page 1 of the Normal table. LOADING... Click here to view page 2 of the Normal table. LOADING...Question content area bottomPart 1a. Identify the null hypothesis and the alternative hypothesis. Choose the correct answer below.Part 7g. What are the critical value(s)?The critical value(s) is/are enter your response here. (Round to three decimal places as needed. Use a comma to separate answers as needed.)Part 8h. What is the area of the critical region?The area is enter your response here. (Round to two decimal places as needed.)Complete parts (a) and (b) below. Click here to view Page 1 of the table of areas under the standard normal curve. Click here to view Page 2 of the table of areas under the standard normal curve. a. The test statistic in a right-tailed test is z= 1.71. Determine the P-value and decide whether, at the 5% significance level, the data provide sufficient evidence to reject the null hypothesis in favor of the alternative hypothesis. The P-value is (Round to three decimal places as needed.) This P-value V sufficient evidence to reject the null hypothesis in favor of the alternative hypothesis because it is V the significance level. b. The test statistic in a right-tailed test is z= - 0.82. Determine the P-value and decide whether, at the 5% significance level, the data provide sufficient evidence to reject the null hypothesis in favor of the alternative hypothesis. The P-value is (Round to three decimal places as needed.) This P-value sufficient evidence to reject the null hypothesis in…Please refer to the image attached. tnxListed below are the numbers of years that archbishops and monarchs in a certain country lived after their election or coronation. Assume that the two samples are independent simple random samples selected from normally distributed populations. Do not assume that the population standard deviations are equal. Use a 0.10 significance level to test the claim that the mean longevity for archbishops is less than the mean for monarchs after coronation, All measurements are in years. ok nch Click the icon to view the table of longevities of archbishops and monarchs. What are the null and alternative hypotheses? Assume that population 1 consists of the longevity of archbishops and population 2 consists of the longevity of monarchs. O B. Ho H1 = H2 H, 2 OA. Ho H1 SH2 correct: er Conter YC. Ho H1 = H2 H, H H2 O D. Ho H1 2 H H P2 for Succes media Lib The test statistic is. (Round to two decimal places as needed.) hase Optio rse ToolsPlease answer and show all work. Thank you!!!Data on the weights (Ib) of the contents of cans of diet soda versus the contents of cans of the regular version of the soda is summarized to the right. Assume that the two samples are independent simple random samples selected from normally distributed populations, and do not assume that the population standard deviations are equal. Complete parts (a) and (b) below. Use a 0.01 significance level for both parts. Diet Regular H2 27 27 0.79037 lb 0.80399 lb 0.00449 lb 0.00756 lb a. Test the claim that the contents of cans of diet soda have weights with a mean that is less than the mean for the regular soda. 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