Consider the function below written in Python3: def foo(a, b=[1]): if a <= 1: return b b_new = [b[i] + b[i+1] for i in range(len(b)-1)] return foo(a-1, [1] + b_new + [1]) The recurrence relation for foo(a, b) when a > 0 and assuming n is the length of b is: T(a, n) = T ( +0(n
Consider the function below written in Python3: def foo(a, b=[1]): if a <= 1: return b b_new = [b[i] + b[i+1] for i in range(len(b)-1)] return foo(a-1, [1] + b_new + [1]) The recurrence relation for foo(a, b) when a > 0 and assuming n is the length of b is: T(a, n) = T ( +0(n
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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![Consider the function below written in Python3:
Consider the function below written in Python3:
def foo(a, b=[1]):
def bar(x, y):
if a <= 1:
if y > 0:
return b
if (y % 2):
b_new = [b[i] + b[i+1] for i in range(len(b)-1)]
return bar(x, y >> 1) + bar(x, y >> 1) + x
return foo(a-1, [1] + b_new + [1])
return bar(x, y >> 1) + bar(x, y >> 1)
else:
return 0
The recurrence relation for foo(a, b) when a > 0 and assuming n is the length of b is:
а,
The recurrence relation for bar(x, y) when x, y > 0 is:
T(а, п) - Т(
+o(n
T(x, y) = 2
+0(1
T
What is the worst-case auxiliary space complexity of bar(, y)?
(Follow/use the same notes above)
Answer:](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fa1f2c132-1439-42c7-b4cb-11c574c8a62f%2F625fe074-61b9-478b-8c74-faf80b1bdb5a%2F0chb9e_processed.png&w=3840&q=75)
Transcribed Image Text:Consider the function below written in Python3:
Consider the function below written in Python3:
def foo(a, b=[1]):
def bar(x, y):
if a <= 1:
if y > 0:
return b
if (y % 2):
b_new = [b[i] + b[i+1] for i in range(len(b)-1)]
return bar(x, y >> 1) + bar(x, y >> 1) + x
return foo(a-1, [1] + b_new + [1])
return bar(x, y >> 1) + bar(x, y >> 1)
else:
return 0
The recurrence relation for foo(a, b) when a > 0 and assuming n is the length of b is:
а,
The recurrence relation for bar(x, y) when x, y > 0 is:
T(а, п) - Т(
+o(n
T(x, y) = 2
+0(1
T
What is the worst-case auxiliary space complexity of bar(, y)?
(Follow/use the same notes above)
Answer:
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