Consider the following. B 0.500 mm 60.0° (a) Red blood cells often become charged and can be treated as point charges. Healthy red blood cells are negatively charged, but unhealthy cells (due to the presence of a bacteria, for example) can become positively charged. In the figure, three red blood cells are oriented such that they are located on the corners of an equilateral triangle. The red blood cell charges are A = 2.10 pC, B = 7.50 pC, and C = -4.10 pC. Given these charges, what would the magnitude and direction of the electric field be at cell A? (1 pC = 1 x 10-12 c.) magnitude What is the equation for the electric field of a point charge? How do you calculate the net electric field at a certain location? What are the components of the fields due to B and C at A's location? N/C direction What are the components of the net electric field? Can you then use these to find the direction?° counterclockwise from the +x-axis (b) If the charge of cell A were doubled, how would the electric field at cell A change? O Does the electric field at cell A include the electric field generated by cell A?The field would be unchanged. O The magnitude of the field would be quadrupled. O The magnitude of the field would be halved. O The magnitude of the field would be doubled.

Principles of Physics: A Calculus-Based Text
5th Edition
ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
Publisher:Raymond A. Serway, John W. Jewett
Chapter19: Electric Forces And Electric Fields
Section: Chapter Questions
Problem 15OQ: Assume the charged objects in Figure OQ19.15 are fixed. Notice that there is no sight line from the...
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Consider the following.
0.500 mm
60,0°
(a) Red blood cells often become charged and can be treated as point charges. Healthy red blood cells are negatively charged, but unhealthy cells (due to the presence of a bacteria, for
example) can become positively charged. In the figure, three red blood cells are oriented such that they are located on the corners of an equilateral triangle. The red blood cell charges
are A = 2.10 pC, B = 7.50 pC, and C = -4.10 pc. Given these charges, what would the magnitude and direction of the electric field be at cell A? (1 pC = 1 x 10-12 c.)
What is the equation for the electric field of a point charge? How do you calculate the net electric field at a certain location? What are the components of the fields due to B
and C at A's location? N/C
magnitude
direction
What are the components of the net electric field? Can you then use these to find the direction?° counterclockwise from the +x-axis
(b) If the charge of cell A were doubled, how would the electric field at cell A change?
O Does the electric field at cell A include the electric field generated by cell A?The field would be unchanged.
O The magnitude of the field would be quadrupled.
O The magnitude of the field would be halved.
O The magnitude of the field would be doubled.
Transcribed Image Text:Consider the following. 0.500 mm 60,0° (a) Red blood cells often become charged and can be treated as point charges. Healthy red blood cells are negatively charged, but unhealthy cells (due to the presence of a bacteria, for example) can become positively charged. In the figure, three red blood cells are oriented such that they are located on the corners of an equilateral triangle. The red blood cell charges are A = 2.10 pC, B = 7.50 pC, and C = -4.10 pc. Given these charges, what would the magnitude and direction of the electric field be at cell A? (1 pC = 1 x 10-12 c.) What is the equation for the electric field of a point charge? How do you calculate the net electric field at a certain location? What are the components of the fields due to B and C at A's location? N/C magnitude direction What are the components of the net electric field? Can you then use these to find the direction?° counterclockwise from the +x-axis (b) If the charge of cell A were doubled, how would the electric field at cell A change? O Does the electric field at cell A include the electric field generated by cell A?The field would be unchanged. O The magnitude of the field would be quadrupled. O The magnitude of the field would be halved. O The magnitude of the field would be doubled.
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