Consider the following java code: int var1 = 15; int var2 = 20; if (var1 >= var2){ else{ var1 = var1 + var2 var1 = var1 -var2
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- code in java pls Summary: Given integer values for red, green, and blue, subtract the gray from each value. Computers represent color by combining the sub-colors red, green, and blue (rgb). Each sub-color's value can range from 0 to 255. Thus (255, 0, 0) is bright red, (130, 0, 130) is a medium purple, (0, 0, 0) is black, (255, 255, 255) is white, and (40, 40, 40) is a dark gray. (130, 50, 130) is a faded purple, due to the (50, 50, 50) gray part. (In other words, equal amounts of red, green, blue yield gray). Given values for red, green, and blue, remove the gray part. Ex: If the input is: 130 50 130 the output is: 80 0 80 Find the smallest value, and then subtract it from all three values, thus removing the gray.A binary operator is an operation that is performed on two operands. For example, addition is a binary operator that adds two operands (e.g., 2 + 4). In the provided UML diagram, all binary operators have two operands and an execute method that performs the appropriate operation on the operands. The AddOperation class should add the two operands. The SubtractOperation class should subtract the two operands. Here is an example of how a binary operator could be used: IBinaryOperator operator = new AddOperator(8, 12);System.out.println(operator.execute()); // should print 20operator.setLeftOperand(18);System.out.println(operation.execute()); // should print 30 crate a Main.java to test your codeConvert the following java code to C++ //LabProgram.javaimport java.util.Scanner;public class LabProgram {public static void main(String[] args) {//defining a Scanner to read input from the userScanner input = new Scanner(System.in);//reading the value for Nint N = input.nextInt();//creating a 1xN matrixint[] m1 = new int[N];//creating an NxN matrixint[][] m2 = new int[N][N];//creating a 1xN matrix to store the resultint[] result = new int[N];//looping and reading N integers into m1for (int i = 0; i < N; i++) {m1[i] = input.nextInt();}//looping from 0 to N-1for (int i = 0; i < N; i++) {//looping from 0 to N-1for (int j = 0; j < N; j++) {//reading an integer and storing it into m2 at position i,jm2[i][j] = input.nextInt();}}//multiply m1 and m2, store result in result//looping from 0 to N-1for (int i = 0; i < N; i++) {//looping from 0 to N-1for (int j = 0; j < N; j++) {//multiplying value at index j in m1 with value at j,i in m2, adding to current value at index i// on…
- Explain the invokeAny() function in Java.Translate the following Java code into VM code. int positiveDivide(int a, int b){ int quotient = 0; int divisor = b; while (divisor <= a) { quotient++; divisor += b; } return quotient;}Java Programming- Need the code- Suppose we have a string holding the text of an entire book. If we want to analyze segments of the text, it is inefficient to make substrings. Instead, we should just store a reference to the original text and the starting and ending positions. Design a class Segment that does this, and have it implement the CharSequence interface of the standard library. Write a test program in which you demonstrate that you can pass your Segment objects to methods that accept CharSequence instances, such as String.join and PrintStream.append.
- Write these in Pseudocode #1a – In pseudocode, write a call to a function that passes 1 Integer variable and 1 Integer array, and saves a Boolean value in return. #1b – In pseudocode, write the function that accepts 1 Integer and 1 Integer array and returns a Boolean. In the function, search the Integer array with a for-loop, and if the Integer parameter is found in the array, return false. If the Integer parameter is not found, return true. #2a – In pseudocode, write a call to a module that passes 1 Integer variable, 1 Real variable, 1 String constant, and 1 String literal as arguments. #2b – In pseudocode, write the module header that accepts 1 Integer, 1 Real, and 2 Strings as parameters. #3 – This pseudocode has multiple problems. Fix the calling statement and the definition below so that the routine accepts 3 grades as parameters and returns the average into a variable.…I am learning Java, but i am a pythonista. So please write this code below in python. Code: public class ABC{ /* Function to reverse arr[] from start to end*/ static void rvereseArray(int arr[], int start, int end) { int temp; while (start < end) { temp = arr[start]; arr[start] = arr[end]; arr[end] = temp; start++; end--; } } /* Utility that prints out an array on a line */ static void printArray(int arr[], int size) { for (int i = 0; i < size; i++) System.out.print(arr[i] + " "); System.out.println(); } // Driver code public static void main(String args[]) { int arr[] = {1, 2, 3, 4, 5, 6}; printArray(arr, 6); rvereseArray(arr, 0, 5); System.out.print("Reversed array is \n"); printArray(arr, 6); }}Given the following: #includ int a[] ={4, 6}, i = 0, y =3, z =1; void f(int x){ int z = 2; g (); X = x + y; z = z +X; i++; return x + a[ i ]+y; } void g(){ z += 3; y = a[i] + z; } void main(){ printf("%d", y + f( a[i] ) - y); } State the output assuming the following: A) Call by reference, dynamic scoping, operands are evaluated right to left. B) Call by name, static scoping; operands are evaluated left to right.
- Write the code in Java language The problem states that there are five philosophers sitting around a circular table. The philosophers must alternatively think and eat. Each philosopher has a bowl of food in front of them, and they require a fork in each hand to eat. However, there are only five forks available. You need to design a solution where each philosopher can eat their food without causing a deadlock.Plz rearrange the code so that it works Step 1 We will solve the given problem in Java language. arrow_forward Step 2 CODE (Student.java) public class Student {private int studentNumber;private int test;private int assignment;private int exam;public Student(int studentNumber, int test, int assignment, int exam) {this.studentNumber = studentNumber;this.test = test;this.assignment = assignment;this.exam = exam;}public int getStudentNumber() {return this.studentNumber;}public void setStudentNumber(int studentNumber) {this.studentNumber = studentNumber;}public int getTest() {return this.test;}public void setTest(int test) {this.test = test;}public int getAssignment() {return this.assignment;}public void setAssignment(int assignment) {this.assignment = assignment;}public int getExam() {return this.exam;}public void setExam(int exam) {this.exam = exam;}} arrow_forward Step 3 CODE (Student_Report.java) public class Student_Report extends Student{public Student_Report(int…ll. ... LabManualProgramming2_Spring2.. → AssignMENts: Question 1: Consider the following declaration: int beta[3][3]; What is stored in beta after each of the following statements executes? a. for (i= 0; i< 3; i++) for (j = 0; j< 3; j++) beta[i][j] = 0; b. for (i = 0; i< 3; i++) for (j = 0; j < 3; j++) beta[i][j] = i+j; c. for (i = 0; i< 3; i++) for (j = 0; j < 3; j++) beta[i][j] = i * j; d. for (i= 0; i< 3; i++) for (j = 0; j<3; j++) beta[i][i] = 2 * (i + j) % 4; 18 | P age Question 2: Write C++ statements that do the following: a. Declare an array alpha of 10 rows and 20 columns of type int. b. Initialize the array alpha to 0. c. Store 1 in the first row and 2 in the remaining rows. d. Store 5 in the first column, and make sure that the value in each subsequent column is twice the value in the previous column. e. Print the array alpha one row per line. f. Print the array alpha one column per line. Question 3: Suppose that you have the following declarations: int times[30][7]; int…