Given the following: #includ int a[] ={4, 6}, i = 0, y =3, z =1; void f(int x){ int z = 2; g (); X = x + y; z = z +X; i++; return x + a[ i ]+y; } void g(){ z += 3; y = a[i] + z; } void main(){ printf("%d", y + f( a[i] ) - y); } State the output assuming the following: A) Call by reference, dynamic scoping, operands are evaluated right to left. B) Call by name, static scoping; operands are evaluated left to right.
Given the following: #includ int a[] ={4, 6}, i = 0, y =3, z =1; void f(int x){ int z = 2; g (); X = x + y; z = z +X; i++; return x + a[ i ]+y; } void g(){ z += 3; y = a[i] + z; } void main(){ printf("%d", y + f( a[i] ) - y); } State the output assuming the following: A) Call by reference, dynamic scoping, operands are evaluated right to left. B) Call by name, static scoping; operands are evaluated left to right.
Chapter2: Using Data
Section: Chapter Questions
Problem 14RQ
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Question
![Given the following:
#includ<sdtio.h>
int a[] ={4, 6}, i = 0, y =3, z =1;
void f(int x){
int z = 2;
g ();
X = x + y;
z = z +X;
i++;
return x + a[ i ]+y;
}
void g(){
z += 3;
y = a[i] + z;
}
void main(){
printf("%d", y + f( a[i] ) - y);
}
State the output assuming the following:
A) Call by reference, dynamic scoping, operands are evaluated right to left.
B) Call by name, static scoping; operands are evaluated left to right.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fb32725b1-ec84-4ed4-99e3-cdb0353624e9%2F6b9fb75c-f07b-4d88-a8d8-e91d2a04b06c%2Fxsm1cs5.png&w=3840&q=75)
Transcribed Image Text:Given the following:
#includ<sdtio.h>
int a[] ={4, 6}, i = 0, y =3, z =1;
void f(int x){
int z = 2;
g ();
X = x + y;
z = z +X;
i++;
return x + a[ i ]+y;
}
void g(){
z += 3;
y = a[i] + z;
}
void main(){
printf("%d", y + f( a[i] ) - y);
}
State the output assuming the following:
A) Call by reference, dynamic scoping, operands are evaluated right to left.
B) Call by name, static scoping; operands are evaluated left to right.
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