Consider the following hypothesis test: HO: p = 0.35 Ha: p > 0.35 From a random sample of n = 100 observational units, the observed sample proportion is 0.27 (p * = 0.27) Based on the information provided, calculate the simulated p-value. Using the simulated p-value, evaluate the claims. a) Not enough evidence against the null hypothesis H0 and in support of the alternative hypothesis Ha. b) Strong evidence against the null hypothesis HO and in support of the alternative hypothesis Ha c) Very strong evidence against the null hypothesis H0 and in support of the alternative hypothesis Ha d) Some evidence against the null hypothesis HO and in support of the alternative hypothesis Ha - This is the table to determine the answer if the p-value is: Strength of Evidence In Support of Ha- Above 0.10 (p-value > 0.10) Not enough evidence against H0 and in support of Ha - Between 0.05 and 0.10 (0.05 < p- value = < 0.10) Some evidence against H 0 and in support of Ha- Between 0.01 and 0.05 (0.01 < p-value = < 0.05) Strong evidence against H0 and in support of Ha- Less than 0.01 (p-value =< 0.01) Very strong evidence against H 0 and in support of HaSimulated Sampling Distribution of hat(p) (from 150 random samples of size n = 100)

Test the clainm that the mean GPA of night students is significantly different than 2.5 at the 0.01 significance level. The null and alternative hypothesis would be: Ho:u > 2.5 Ho:p 0.625 Ho:p 0.625 H1:µ> 2.5 H :µ+ 2.5 H1:p 0.625 The test is: right-tailed left-tailed two-tailed Based on a sample of 55 people, the sample mean GPA was 2.46 with a standard deviation of 0.07 The p-value is: (to 2 decimals) Based on this we: O Fail to reject the null hypothesis O Reject the null hypothesis

Test the claim that the mean GPA of night students is smaller than 2.1 at the .005 significance level.The null and alternative hypothesis would be: H0:p=0.525H0:p=0.525H1:p<0.525H1:p<0.525 H0:p=0.525H0:p=0.525H1:p>0.525H1:p>0.525 H0:p=0.525H0:p=0.525H1:p≠0.525H1:p≠0.525 H0:μ=2.1H0:μ=2.1H1:μ≠2.1H1:μ≠2.1 H0:μ=2.1H0:μ=2.1H1:μ<2.1H1:μ<2.1 H0:μ=2.1H0:μ=2.1H1:μ>2.1H1:μ>2.1 The test is: left-tailed right-tailed two-tailed Based on a sample of 75 people, the sample mean GPA was 2.06 with a standard deviation of 0.07The test statistic is:  (to 2 decimals)The critical value is:  (to 2 decimals)Based on this we: Fail to reject the null hypothesis Reject the null hypothesis

Determine the decision criterion for rejecting the null hypothesis in the given hypothesis test; i.e., describe the values of the test statistic that would result in rejection of the null hypothesis, suppose you wish to test the claim that Md, the mean value of the difference d for a population of unpaired data is greater than 0. Given samples n1=26 and n2=49 and a significance level of a=0.05, what criterion would be used for rejecting the null hypothesis?

B. Identify the test statistic. z=___ C. Identify the​ P-value. ​P-value=___   D. What is the conclusion based on the hypothesis​ test?  The​ P-value is (greater than/ less than) the significance level of α=0.05​, so (reject/ fail to reject) the null hypothesis. There (suffiecient/ is not sufficient) evidence to warrant rejection of the claim that women and men have equal success in challenging calls.   Test the claim by constructing an appropriate confidence interval. The 95​% confidence interval is___<(p1-p2)<____.   E. What is the conclusion based on the confidence​ interval? Because the confidence interval limits (include/ do not include) 0, there (does/ does not) appear to be a significant difference between the two proportions. There (is sufficient/ is not sufficient) evidence to warrant rejection of the claim that men and women have equal success in challenging calls.   F. Based on the​ results, does it appear that men and women may have equal success in challenging​…

7) Consider the computer output shown below: One-Sample T:Y Test of mu =91 vs. not = 91 Variable Mean Std. Dev. SE Mean 95% CI 25 92.5805 (91.6160, ? ) 0.4675 3.38 0.002 (a) Fill in the missing values in the output. Can the null hypothesis be rejected at the 0.05 level? Why? (b) Is this a one-sided or two-sided test?

Utilizing the previous table: A sample of 25 cities have been classified as high or low on their homicide rates and on the number of handguns sold within the city limits. Was the null hypothesis rejected or accepted?

The P-value for a hypothesis test is shown. Use the P-value to decide whether to reject. Ho when the level of significance is (a) a = 0.01, (b) a = 0.05, and (c) a=0.10. P=0.0411 (a) Do you reject or fail to reject Ho at the 0.01 level of significance? OA. Fail to reject Ho because the P-value, 0.0411, is greater than a = 0.01. OB. Fail to reject Ho because the P-value, 0.0411, is less than a =0.01. OC. Reject Ho because the P-value, 0.0411, is greater than a = 0.01. OD. Reject Ho because the P-value, 0.0411, is less than a = 0.01 (b) Do you reject or fail to reject Ho at the 0.05 level of significance? O A. Reject Ho because the P-value, 0.0411, is greater than a = 0.05. OB. Fail to reject Ho because the P-value, 0.0411, is less than a = 0.05. OC. Fail to reject Ho because the P-value, 0.0411, is greater than a = 0.05. O D. Reject Ho because the P-value, 0.0411, is less than a = 0.05. CECO

You may need to use the appropriate appendix table or technology to answer this question. Consider the following hypothesis test. H0: p ≥ 0.85 Ha: p < 0.85 A sample of 160 items was selected. Compute the p-value and state your conclusion for each of the following sample results. Use ? = 0.05. (a) p = 0.78 (b) p = 0.82 (c) p = 0.80 (d) p = 0.88

An experimenter flips a coin 100 times and gets 54 heads. Test the claim that the coin is fair against the two-sided alternative.  (Null and Alternate Hypothesis and Test Statistic) A. Ho: p = 0.50; Ha: p < 0.50; z = 0.800 B. Ho: p = 0.50; Ha: p > 0.50; z = 0.800 C. Ho: p = 0.50; Ha: p > 0.50; z = 0.081 D. Ho: p = 0.50; Ha: p ≠ 0.50; z = 0.800 E. Ho: p = 0.50; Ha: p ≠ 0.50; z = 0.081    (p-value and conclusion) A. p = 0.540; FRHo (No sufficient evidence to reject the claim) B. p = 0.424; RHo (Sufficient evidence exists to reject the claim) C. p = 1.576; FRHo (No sufficient evidence to reject the claim) D. p = 0.424; FRHo (No sufficient evidence to reject the claim) E. p = 1.576; RHo (No sufficient evidence to reject the claim)