Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN: 9780133594140
Author: James Kurose, Keith Ross
Publisher: PEARSON
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- 24. Consider the following grammar : stmt → if expr then expr else expr; stmt | ɛ → term relop term | term → id | number expr - term id → a|b|c number [0-9] where relop is a relational operator (e.g >, <, ....), ɛ refers to the empty statement, and if, then, else are terminals. Consider a program P following the above grammar containing ten if terminals. The number of control flows paths in P is For example, the program if e1 then e2 else e3 has 2 control flow paths, e1 → e2 and e1 → e3. O 10 1024 20 O 2048arrow_forwardExplain the abab string in the following ambiguous grammar:arrow_forward1. Consider the following grammar and try to find out Operator Precedence and Associativity. Is the grammar Ambiguous? If so, find a string for which it is ambiguous and finally, convert to Unambiguous grammar without changing the original Language. S → S % A/ A A → B * A/ B В — В & C/С C → S/ idarrow_forward
- . Consider the following grammar (G1) for simple assignment statements. (The symbols that begin with upper-case letters are variables and Assign is the start variable.) Assign Id := Expr Id → abc Expr | Expr * Expr |(Expr) | Id Expr → Expr a) Give a (leftmost) derivation for string a := b ⋆ a — c. b) Give a parse tree for string a := b ⋆ a — c.arrow_forwardThe following is a context-free grammar G: V={A,B,C} S={a,b} vO=S S->A A alb| A B A->B S ala B->B al\e Convert G into an equivalent context-free grammar in Chomsky normal form. a) Show your grammar rules after Step 1 b) Show your grammar rules after Step 2 c) Show your grammar rules after Step 3 d) Show your grammar rules after Step 4arrow_forwardLet E = {a,b}. Find the language generated by following grammar: (1) S- aSb| a (2) S- AS S- aSb| b A - a4| .arrow_forward
- Solve it wrong answer downvotearrow_forwardSelect the Context Free Grammar below that is in the form of Chomsky Normal Form. G=( {S,a,b}, {0,1}, S, {S0b|1a, a0|OS|1aa, b➡1|1s|Obb}) ☐ G=( {S,a,b}, {0,1}, S, {Sab|1, a0|1|Sa, b→1|bs}) ☐ G=( {S,A,B}, {a,b}, S, {S AB|bA, Aa|b|SB, B→a|SB}) ☐ G=( {S,A,B}, {a,b}, S, {S-BB|b, A➡a|b|SS, B→a|SA})arrow_forwardexpr term_tail term factor_tail id = expr | term term_tail + term term_tail | E factor factor_tail → * factor factor_tail | e factor → (expr) | id Explain why the grammar above is not LL(1). Be specific.arrow_forward
- Write the FIRST and FOLLOW sets for this grammararrow_forward1. The grammar is known as follows:P → H | PbdHH → a | (P)Asked: b. Please Make an SLR table from the grammar abovearrow_forwardQuestion 2-Context-free Grammars Consider the alphabet = {A, V., (,), x, y, z) and the following grammar G = (V,E, R, F), defined by the rules: F (FAF) | (FVF) | (F) | P (a) Identify the set of variables and the set of terminal symbols of G. (b) Identify three words (of lengths between 10 and 20) that can be generated by the above grammar and show their derivations. (c) Consider a modified grammar G', where we remove the brackets '(' and ')' from the alphabet and the derivation rules. That is we set Σ'= {A, V., x, y, z) and we remove all occurrences of brackets in the derivation rules. Show that there are words that are derived ambiguously in G'arrow_forward
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