Consider the Earth and a cloud layer 800 m above the planet to be the plates of a parallel-plate capacitor.(a) If the cloud layer has an area of 4.0 km² = 4000000 m², what is the capacitance?[Input box for answer] F(b) If an electric field strength greater than 3.0 × 10⁶ N/C causes the air to break down and conduct charge (lightning), what is the maximum charge the cloud can hold?[Input box for answer] C

Answered: Image /qna-images/answer/df745f30-18fc-4aa8-850f-2c7c15368da6.jpg

Consider the Earth and a cloud layer 800 m above the planet to be the plates of a parallel-plate capacitor. (a) If the cloud layer has an area of 4.0 km² = 4000000 m², what is the capacitance? F (b) If an electric field strength greater than 3.0 x 106 N/C causes the air to break down and conduct charge (lightning), what is the maximum charge the cloud can hold? C

Consider the Earth and a cloud layer 800 m above the planet to be the plates of a parallel-plate capacitor. (a) If the cloud layer has an area of 4.0 km² = 4000000 m², what is the capacitance? F (b) If an electric field strength greater than 3.0 x 106 N/C causes the air to break down and conduct charge (lightning), what is the maximum charge the cloud can hold? C

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

See similar textbooks

Similar questions

A certain parallel-plate capacitor consists of two plates, each with area 2.00 x 102cm2, and separated by a gap of 0.400 cm. (Assume air as the dielectric material.) a) What is the capacitance of this capacitor? b) If the capacitor is connected across a 500.0 V source, what charge will it hold? c) What is the magnitude of the electric field between the plates of the capacitor? (under the conditions of part b)?
Assume you have a charged capacitor that stores 1.10 x 10-12 J of energy while connected to a 1.50-V battery. If this capacitor has circular plates of radius 1.34 cm, how much charge is on these plates when it is fully charged?
A 7.44 µF isolated capacitor is constructed with Teflon, having a dielectric constant of 2.10, between the plates. The capacitor is initially charged to 1.34 volts, and then the Teflon is removed. After removing the Teflon, what is the potential difference across the capacitor plates?
Consider a parallel-plate capacitor made up of two conducting plates with dimensions 34 mm × 18 mm. a) If the separation between the plates is 1.1 mm, what is the capacitance, in pF, between them? b) If there is 0.32 nC of charged stored on the positive plate, what is the potential, in volts, across the capacitor? c) What is the magnitude of the electric field, in newtons per coulomb, inside this capacitor? d) If the separation between the plates doubles, what will the electric field be if the charge is kept constant?
Regarding the Earth and a cloud layer 650 m above the Earth as the "plates" of a capacitor, calculate the capacitance if the cloud layer has an area of 1.53 km2. If an electric field of 2.0 × 106 N/C makes the air breakdown and conduct electricity (lightning), what is the maximum charge the cloud can hold? εo = 8.85 x 10−12 F/m
A capacitor with parallel, circular plates has a constant charge of equal and opposite sign on the the plate between which there is the void. The geometric dimensions of the capacitor (diameter and distance between the plates) are d oubled. If the initially stored energy density was Uo, what is the new energy density? Ou 14 or O 4 u Ou / 16 or O 16u ing
A certain parallel-plate capacitor is filled with a dielectric for which κ = 6.26. The area of each plate is 0.0573 m2, and the plates are separated by 2.35 mm. The capacitor will fail (short out and burn up) if the electric field between the plates exceeds 164 kN/C. What is the maximum energy that can be stored in the capacitor?
A parallel-plate capacitor is constructed using a dielectric material whose dielectric constant is 3.30 and whose dielectric strength is 1.20 x 108 V/m. The desired capacitance is 0.300 μF, and the capacitor must withstand a maximum potential difference of 4.00 kV. Find the minimum area of the capacitor plates. m²
Consider a parallel plate capacitor having plates of area 1.4 cm2 that are separated by 0.018 mm of neoprene rubber. You may assume the rubber has a dielectric constant κ = 6.7. a) What is the capacitance in μF? b) What charge, Q, in coulombs, does it hold when 9.00 V is applied to it?
Consider a cylindrical capacitor with inner radius 10.0 cm, outer radius 12.0 cm, and length 50.0 cm. A dielectric with dielectric constant k of 12.5 fills the volume between the two cylinders. The capacitor is connected to a 100 V battery and charged completely. What is the charge on the capacitor? a.) 12.897 nC b.) 16.718 nC c.) 18.012 nC d.) 19.062 nC
An air-filled parallel-plate capacitor has plates of area 2.10 cm2 separated by 2.10 mm. The capacitor is connected to a(n) 11.0 V battery. (a) Find the value of its capacitance. X PF (b) What is the charge on the capacitor? X pC
Consider a parallel-plate capacitor having an area of 2550 mm^2 and a plate separation of 4.9mm and with a material of dielectric constant 5.9 positioned between the plates. Also, the value of E0 is 8.85x10^-12F/m. a) What is the capacitance of this capacitor in pF? b) compute the electric field that must be applied for a charge pf 7.8x10^-8C to be stored on each plate in V/m.