Consider the Earth and a cloud layer 800 m above the planet to be the plates of a parallel-plate capacitor. (a) If the cloud layer has an area of 4.0 km² = 4000000 m², what is the capacitance? F (b) If an electric field strength greater than 3.0 x 106 N/C causes the air to break down and conduct charge (lightning), what is the maximum charge the cloud can hold? C

Consider a parallel-plate capacitor made up of two conducting plates with dimensions 34 mm × 18 mm. a) If the separation between the plates is 1.1 mm, what is the capacitance, in pF, between them?  b) If there is 0.32 nC of charged stored on the positive plate, what is the potential, in volts, across the capacitor?  c) What is the magnitude of the electric field, in newtons per coulomb, inside this capacitor?  d) If the separation between the plates doubles, what will the electric field be if the charge is kept constant?

Regarding the Earth and a cloud layer 650 m above the Earth as the "plates" of a capacitor, calculate the capacitance if the cloud layer has an area of 1.53 km2. If an electric field of 2.0 × 106 N/C makes the air breakdown and conduct electricity (lightning), what is the maximum charge the cloud can hold?  εo = 8.85 x 10−12 F/m

A certain parallel-plate capacitor is filled with a dielectric for which κ = 6.26. The area of each plate is 0.0573 m2, and the plates are separated by 2.35 mm. The capacitor will fail (short out and burn up) if the electric field between the plates exceeds 164 kN/C. What is the maximum energy that can be stored in the capacitor?

A parallel-plate capacitor is constructed using a dielectric material whose dielectric constant is 3.30 and whose dielectric strength is 1.20 x 108 V/m. The desired capacitance is 0.300 μF, and the capacitor must withstand a maximum potential difference of 4.00 kV. Find the minimum area of the capacitor plates. m²

Consider a parallel plate capacitor having plates of area 1.4 cm2 that are separated by 0.018 mm of neoprene rubber. You may assume the rubber has a dielectric constant κ = 6.7. a) What is the capacitance in μF?  b) What charge, Q, in coulombs, does it hold when 9.00 V is applied to it?

An air-filled parallel-plate capacitor has plates of area 2.10 cm2 separated by 2.10 mm. The capacitor is connected to a(n) 11.0 V battery. (a) Find the value of its capacitance. X PF (b) What is the charge on the capacitor? X pC

Consider a parallel-plate capacitor having an area of 2550 mm^2 and a plate separation of 4.9mm and with a material of dielectric constant 5.9 positioned between the plates. Also, the value of E0 is 8.85x10^-12F/m. a) What is the capacitance of this capacitor in pF? b) compute the electric field that must be applied for a charge pf 7.8x10^-8C to be stored on each plate in V/m.

Regarding the Earth and a cloud layer 800 m above the Earth as the "plates" of a capacitor, calculate the capacitance. Assume the cloud layer has an area of 1 km2 and that the air between the cloud and the ground is pure and dry. nF   Assume charge builds up on the cloud and on the ground until a uniform electric field of 2.0 106 N/C throughout the space between them makes the air break down and conduct electricity as a lightning bolt. What is the maximum charge the cloud can hold? C