Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN: 9780133923605
Author: Robert L. Boylestad
Publisher: PEARSON
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Question
Consider the Common Emitter (CE) amplifier below. The capacitor Cn = 1 µF, Vcc = 12 V, Br = 150, and the low cut-off frequency is 100 Hz. Assume VBE = 0.7 V. VCE SAT for this BJT transistor is 0.2 V. Rc = 8002, and Re=120 2. The quiescent collector current is 5 mA Rg2 Rc VIN H Cin R81 RE CE (1) Draw the small signal model for the CE amplifier (11) What is the transconductance gain of the amplifier? (II) What is the voltage gain of the amplifier – with and without a bypass capacitor (Ce)? (IV) Determine a suitable value for the bypass capacitor CE.
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Transcribed Image Text:Consider the Common Emitter (CE) amplifier below. The capacitor Cn = 1 µF, Vcc = 12 V, Br = 150, and the low cut-off frequency is 100 Hz. Assume VBE = 0.7 V. VCE SAT for this BJT transistor is 0.2 V. Rc = 8002, and Re=120 2. The quiescent collector current is 5 mA Rg2 Rc VIN H Cin R81 RE CE (1) Draw the small signal model for the CE amplifier (11) What is the transconductance gain of the amplifier? (II) What is the voltage gain of the amplifier – with and without a bypass capacitor (Ce)? (IV) Determine a suitable value for the bypass capacitor CE.
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