Consider the code full="L do nor like green eggs and ham. lilke themisam- I-am! I do nor which uf me followng evaluares to Tfre? a) x. count ("ham") =3' b) X. count ("do") == 2 C) X. index ('not ")== 10 d) len(y) ==3 es %3D ニニ Ten (x):= 14 f) Ten (x)==13 2 Ten ly) ==2 X.count ("sam") == |

(Intro to Java) Pls answer asap Write Answers Neatly Thanks

] ] is_bipartite In the cell below, you are to write a function "is_bipartite (graph)" that takes in a graph as its input, and then determines whether or not the graph is bipartite. In other words, it returns True if it is, and False if it is not. After compiling the above cell, you should be able to compile the following cell and obtain the desired outputs. print (is_bipartite({"A" : ["B", "C"], "B" : ["A"], "C" : ["A"]}), is_bipartite({"A" : ["B", "C"], "B" : ["A", "C"], "C" : ["A", "B"]})) This should return True False Python Python

please name this cards.py. You may use the following code in your program: import random SUITS = "♠ ♡ ♢ ♣".split()RANKS = "2 3 4 5 6 7 8 9 10 J Q K A".split() def create_deck(shuffle=False):    """Create a new deck of 52 cards"""    deck = [(s, r) for r in RANKS for s in SUITS]    if shuffle:        random.shuffle(deck)    return deck This code creates a random deck of cards (each card is a tuple consisting of a rank and suit).  You are to ask the user how many 5-card hands to play and will keep track of the following poker hands.  You will need to reshuffle the deck as many times as necessary to get the required number of hands.   An example run of the program is as follows. Enter the number of hands to deal: 10000Hand          % of Hands  Hands of Type2 of a kind    41.290%    4129      3 of a kind     1.970%    197       4 of a kind     0.010%    1         2 pair          4.860%    486       Full house      0.150%    15        Flush           0.220%    22         If you deal enough…

q -> (p ^ r)  What is the truth value of the following statement when p is false, q is false and r is true?

Specification: Read sentences from the user until * is entered. Show the number of words in each sentence that contain a stretch of non-z characters with exactly 2 vowels. A stretch starts from the start of the word or after a 'z'. A stretch terminates just before another 'z' or at the end of the word. Examples: 1. Matching words: zoo, azozooza, GONZALEZ 2. Non-matching words: ozo, azoooza The sentences contain no punctuation, the words are separated by one or more spaces, and the characters may be upper or lower case. Keep reading sentences until the user enters "*". Sample I/O: Sentence: azoooza azooza zoo azoo Matching words = 3 Sentence: GONZALEZ passes the ball to VAZQUEZ Matching words = 3 Sentence: azozototzeti Matching words = 1 Sentence: * Done

How can you get the integer value of an enumerator?

] ] get_nhbr In the cell below, you are to write a function called "get_nhbr(Ist, graph)" that takes in two inputs: a list of vertices and a graph. The function is to return a list that contains the neighborhood of the vertices in 'Ist' (remember that this means you are finding the union of the individual vertices' neighborhoods). + Code + Markdown After compiling the above cell, you should be able to compile the following cell and obtain the desired outputs. print (get_nhbr(["A", "D"], {"A" : ["B"], "B" : ["A", "D", "E"], "C" : ["E"], "D":["B"], "E":["B","C","F"], "F":["E"]}), get_nhbr(["B", "C", "F"], {"A" : ["B"], "B" : ["A", "D", "E"], "C" : ["E"], "D":["B"], "E":["B","C","F"], "F":["E"]})) This should return ["B"] ["A", "D", "E"] Python Python