College Physics
11th Edition
ISBN: 9781305952300
Author: Raymond A. Serway, Chris Vuille
Publisher: Cengage Learning
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- Consider the circuit shown in the figure, with C₁ = 2.42 μF and C₂ = 7.54 µF. 2 2.00 µF 6.00 µF + 90.0 V 1 C₂ (a) Find the equivalent capacitance (in µF) of the system. UF (b) Find the charge (in μC) on each capacitor. 2.42 μF capacitor UC 6.00 μF capacitor 7.54 µF capacitor 2.00 µF capacitor 오오오 (c) Find the potential difference (in V) on each capacitor. 2.42 μF capacitor V 6.00 μF capacitor V 7.54 µF capacitor V 2.00 uF capacitor V (d) Find the total energy (in m3) stored by the group. mJarrow_forwardThe circuit in the figure below contains a 9.00 V battery and four capacitors. The two capacitors on the left and right both have same capacitance of C, = 8.40 µF. The capacitors in the top two branches have capacitances of 6.00 µF and C, = 2.40 µF. 6.00 µF C 9.00 V (a) What is the equivalent capacitance (in uF) of all the capacitors in the entire circuit? (b) What is the charge (in µC) stored by each capacitor? right 8.40 µF capacitor left 8.40 µF capacitor 2.40 µF capacitor 6.00 µF capacitor (c) What is the potential difference (in V) across each capacitor? (Enter the magnitudes.) right 8.40 µF capacitor V left 8.40 µF capacitor 2.40 µF capacitor V 6.00 µF capacitor Varrow_forwardConsider the circuit shown in the figure, with C₁ = 4.62 μF and C₂ = 7.44 μF. 2.00 µF 6.00 µF + 90.0 V C₂ (a) Find the equivalent capacitance (in µF) of the system. μF (b) Find the charge (in µC) on each capacitor. 4.62 μF capacitor 6.00 μF capacitor 7.44 μF capacitor 2.00 μF capacitor 9999 μC μC μC (c) Find the potential difference (in V) on each capacitor. 4.62 µF capacitor V 6.00 μF capacitor V 7.44 μF capacitor V 2.00 μF capacitor V (d) Find the total energy (in mJ) stored by the group. mJarrow_forward
- Consider the circuit shown below where four capacitors, C1=3.8 μF , C2=4.5 μF , C3=3.6 μF and C4=2.7 μF are connected to a battery of voltage V=21 V. Determine the charge on C1. Express your answer using one decimal place in units of μC.arrow_forwardFind the following. (In the figure, use C, = 31.00 µF and C, = 25.00 µF.) 6.00 µF C2 µF CµF 9.00 V (a) the equivalent capacitance of the capacitors in the figure above uF (b) the charge on each capacitor on the right 31.00-µF capacitor on the left 31.00-µF capacitor μC on the 25.00-µF capacitor on the 6.00-µF capacitorarrow_forwardFour capacitors are connected as shown in the figure below. (C = 18.0 μF.) C 3.00 με th a 6.00 με |20.0 με HH i (a) Find the equivalent capacitance between points a and b. μF (b) Calculate the charge on each capacitor, taking AV ab 20.0 μF capacitor 6.00 μF capacitor 3.00 µF capacitor capacitor C 9999 HC HC HC - = 20.0 V.arrow_forward
- Consider the circuit shown in the figure, with C₁ = 6.92 µF and C₂ = 6.84 µF. 2.00 µF 6.00 µF + 90.0 V (a) Find the equivalent capacitance (in μF) μF (b) Find the charge (in µC) on each capacitor. 6.92 μF capacitor 6.00 μF capacitor 6.84 μF capacitor 2.00 μF capacitor mJ 9999 (c) Find the potential difference (in V) on each capacitor. 6.92 μF capacitor V 6.00 μF capacitor V 6.84 μF capacitor 2.00 μF capacitor the system. V (d) Find the total energy (in mJ) stored by the group.arrow_forwardFind the total capacitance of the combination of capacitors shown in the figure below. (C, = 2.92 µF, C, = 17.7 µF.) %3D µF 1.50 uF 8.00 uF 3.50 uµF 0.750 µFarrow_forwardConsider the circuit shown in the figure, with C₁ = 5.02 μF and C₂ = 6.64 μF. 2.00 µF 6.00 uF + 90.0 V C₂ (a) Find the equivalent capacitance (in µF) of the system. 4.27 μF (b) Find the charge (in µC) on each capacitor. 5.02 µF capacitor HC 6.00 μF capacitor με 6.64 μF capacitor 2.00 μF capacitor με μC (c) Find the potential difference (in V) on each capacitor. 5.02 μF capacitor 6.00 μF capacitor 6.64 μF capacitor 2.00 μF capacitor V (d) Find the total energy (in mJ) stored by the group. mJarrow_forward
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