Consider an electrochemical cell involving Iron and Lead. Fe2+, (aq) +2e-→ Fe(s) E° = -0.45 V Pb2+ (ag) + 2e- Pb(s) E° = -0.13 V Identify the anode Choose... Identify the cathode Choose... + What is the standard reduction Choose... + potential of Lead (Pb)? Towards which electrode anions from Choose... the salt bridge move? What is the potential of this cell under Choose... standard conditions? Which electrode will gain mass? Choose... +

11. What is AG° for the reaction driving the following voltaic cell? Co (s) | Co²+ (aq) || Mn³+ (aq), Mn²+ (aq) | Pt (s) A. -175 kJ +175 kJ B. -351 kJ +351 kJ C. -527 kJ D. E.

A voltaic cell using Pb²⁺/Pb and Ni²⁺/Ni half-cells is set up at standard conditions, and each compartment has a volume of 355 mL. What is the cell potential, in V, after it has delivered 0.150 A for 51.0 hours at 25 °C? (E° for Pb²⁺/Pb = -0.130 V and E° for Ni²⁺/Ni = -0.250 V.)

A standard galvanic cell is constructed in which a Pb2+ | Pb half cell acts as the cathode. Which of the following statements are correct? Hint: Refer to a table of standard reduction potentials. (Choose all that apply.) The anode compartment could be I2|I-. The cathode reaction is Pb2+ + 2e- -> Pb Pb is oxidized at the cathode. Pb2+ is reduced at the cathode. In the external circuit, electrons flow from the other compartment to the Pb2+|Pb compartment.

Refer to the galvanic cell below (the contents of each half-cell are written beneath each compartment): Ni Ag 1.0 M Ni2+ 1.0 M Ag* The standard reduction potentials are as follow: Ni2+ + 2 e- → Ni(s), E° = -0.25 Ag* + e - Ag(s), E° = 0.7996 When current is allowed to flow, which species is oxidised? Select one: а. Ag b. Cannot be determined from the data given. C. Ni2+ O d. Ag* O e. Ni

A voltaic cell is constructed with an Ag/Ag+ half-cell and a Pb/Pb+2 half cell.  All solutions are 1.0 M.   Ag+(aq) + e- → Ag(s) E° = 0.80 V Pb+2(aq) + 2e- → Pb(s) E° = -0.13 V a.Diagram the cell, labeling electrodes and solutions, show the direction of electron flow in the circuit and what occurs in the salt bridge.  b. If the cell were made with [Pb+2] = 0.10 M and [Ag3+] = 3.0 M, would the voltage increase, decrease, or remain the same? Explain using Q.   c.Identify the electrode that is gaining mass

Enter electrons as e". A voltaic cell is constructed in which the anode is a Mn Mn2+ half cell and the cathode is a CI|Cl, half cell. The half- cell compartments are connected by a salt bridge. (Use the lowest possible coefficients. Be sure to specify states such as (aq) or (s). If a box is not needed, leave it blank.) The anode reaction is: The cathode reaction is: The net cell reaction is: In the external circuit, electrons migrate v the Mn|Mn2+ electrode | v the Cl|Cl, electrode. In the salt bridge, anions migrate v the Cl|Cl2 compartment v the Mn|Mn²+ compartment. +

Consider the following voltaic cellat 25°C: Al(s) | Al3*(0.20 M, aq) || Al3+(0.75 M, aq) | Al(s) If the standard reduction potential for the Al3+(aq) /Al(s) redox couple is -1.66 V, what is the overall cell reaction and the cell potential of the voltaic cell shown above? (Reference the cell as written above.) The overall cell reaction is Al3+(0.75 M, aq) AIS*(0.20 M, ag) and E°cell = +0.0113 V. There is no overall cell reaction and E°cell = 0.00 V. The overall cell reaction is Al3+(0.20 M, aq) Als*(0.75 M, aq) and E°cell = +0.0113 V. The overall cell reaction is Al3+(0.20 M, aq) →A13+(0.75 M, ag) and E°cell| = -0.0113 V. The overall cell reaction is Al3*(0.75 M, aq) →AI3*(0.20 M, aq) and E°cell = -0.0113 V. None of these

12. A typical car/truck battery is a cell made by transferring 2 e- by a reaction between lead and sulfuric acid. If the voltage produced (Eᵒcell) is 12 V, what is AG° of this reaction at 25° C? AG° =

What is the voltage of the following cell? Use the Reduction Potential Table found in Chapter 17 notes. Cr(s)|Cr³*(0.25 M) || |2(s)|1-(0.20 M)|Pt(s)