Consider a projectile launched at a height h feet above the ground and at an angle 0 with the horizontal. If the initial velocity is vo feet per second, the path of the projectile is modeled by the parametric equations x = t(vo cos(0)) and y = h + (v, sin 0)t - 16t2. A rectangular equation for the path of this projectile is y = 7+ x - 0.008x2. (a) Eliminating the parameter t from the position function for the motion of a projectile to shows that the rectangular equation is as follows. -16 (sec(0))2 y = x2 + tan(0)x + h (b) Find h, vo, and 0. (Round your answers to two decimal places.) Vo = (c) Use a graphing utility to graph the rectangular equation for the path of the projectile. Confirm your answer in part (b) by sketching the curve represented by the parametric equations. 60 50 40 30 20 50 100 150 10 50 100 150 60 50 60 50 40 40 30 30 20 10 20 50 100 150 10 20 40

A particle initially located at the origin has an acceleration of a = 4.00j m/s? and an initial velocity of v = 9.00î m/s. (a) Find the vector position of the particle at any time t (where t is measured in seconds). tî + 2 j) m (b) Find the velocity of the particle at any time t. î + tj) m/s (c) Find the coordinates of the particle at t = 6.00 s. y%3D m (d) Find the speed of the particle at t = 6.00 s. m/s Need Help? Read It Watch It P Type here to search

You can use any coordinate system you like in order to solve a projectile motion problem. To demonstrate the truth of this statement, consider a ball thrown off the top of a building with a velocity v at an angle 0 with respect to the horizontal. Let the building be 54.0 m tall, the initial horizontal velocity be 9.10 m/s, and the initial vertical velocity be 10.5 m/s. Choose your coordinates such that the positive y-axis is upward, and the x-axis is to the right, and the origin is at the point where the ball is released. (a) With these choices, find the ball's maximum height above the ground and the time it takes to reach the maximum height. maximum height above ground time to reach maximum height (b) Repeat your calculations choosing the origin at the base of the building. maximum height above ground time to reach maximum height

The velocity of a particle as a function of time is given by v(t)=(3t-t )i-4 j all in S.I. units. a) What are the dimensions of the "-1 " in the – ti term? What are the units of the "3 " in the 3t i term? b) Find the position vector of the particle, r(t), if r(0) = -5 i- 2j :) Find the time ti > 0 when the position in the i direction is a maximum. d) Find a 1 -> 3 the average acceleration vector in the time interval 1 to 3 seconds.

(a) You are standing on one side of a river and a tree is directly across from you. You then walk adistance d along the river and determine that now the tree is at an angle θ. How wide is the river?A plane travels north at speed v0 for a time t0 and then travels east at 12v0 for a time 3t0. (b) How farto the north did the plane travel? How far to the east? (c) What is the total distance the plane is awayfrom its initial position?

The position vector r describes the path of an object moving in space. Find the velocity v (t), speeds (t), and acceleration a (t), of the object. r(t) = (et cos(t), et sin(t), et) v(t) = +

A small metal ball is kicked from the edge of a cliff. Its x- and y-coordinates as functions of time are given by x = 19.9t and y = 3.60t - 4.90t2, where x and y are in meters and t is in seconds. (Do not include units in your answer.) (a) Write a vector expression for the ball's position as a function of time (in m), using the unit vectors î and ĵ. (Give the answer in terms of t.) r = By taking derivatives, do the following. (b) Obtain the expression for the velocity vector v as a function of time (in m/s). (Give the answers in terms of t.) V = a = (c) Obtain the expression for the acceleration vector a as a function of time (in m/s²). m/s² m r = (d) Next, use unit-vector notation to write expressions for the position, the velocity, and the acceleration of the metal ball at t = 2.76 s. (Assume the position is in m, the velocity is in m/s and the acceleration is in m/s².) ✓ = m/s a m m/s m/s²

The position r of a particle moving in an xy plane is given by ř seconds. In unit-vector notation, calculate (a) 7, (b) V , and (c) a for t = 3.00 s. (d) What is the angle between the positive direction of the x axis and a line tangent to the particle's path at t = 3.00 s? Give your answer in the range of (-180°; 180°). (4.00r3 – 1.00t)î + (5.00 – 1.00r4)j with 7 in meters and t in (a) Number i i Units (b) Number ît i Units i (c) Number i i Units (d) Number i Units

A drone's velocity at two times 10 s apart is given by the following vectors: ( 7 17 ) m/s ( 12 3 ) m/s Find the direction of the change in velocity vector . Take to the right as +x and up as +y. Give answer between zero and 360 degrees counterclockwise from the +x axis. Make sure you get the correct quadrant and that your calculator is in degrees.