Consider a parallel-plate capacitor with plate's area A = 39.3 cm² and separation between the plates d = 3.8 mm. What are the charge and energy stored on the capacitor if it is connected to a 70-Volt battery? The capacitor is filled with air. The charge, Q₁ = 9.0651303 x Units Select an answer The energy, U₁ = 2.24175E-X Units Select an answer If a dielectric material with K= 1.85 is inserted so that it fills the space between the plates (with the capacitor still connected to the same battery), what are the new changre and energy on the capacitor? The new charge, Q₂ = The new energy, U₂: = Units Select an answer Units Select an answer

100 There is a system with four capacitors connected, as shown in Figure P25.10. (a) Calculate the equivalent capacity between points a and b. (b) Find the charge amount of each capacitor when the potential difference AV between points a and bis 15.0 V. 11 (13). Find the equivalent capacitance a 15.0μF 3.00 μF 120.0 με 16: HH 6.00 με Figure P25.10

A parallel-plate capacitor has capacitance C0 = 8.00 pF when there is air between the plates. The separation between the plates is 1.20 mm. Express your answer with the appropriate units. Part A: What is the maximum magnitude of charge that can be placed on each plate if the electric field in the region between the plates is not to exceed 3.00×104 V/m? Part B: A dielectric with K = 2.70 is inserted between the plates of the capacitor, completely filling the volume between the plates. Now what is the maximum magnitude of charge on each plate if the electric field between the plates is not to exceed 3.00×104 V/m?

1. A parallel-plate capacitor has square plates that have a length equal to 1.4 cm separated by 1 mm. It is connected to a battery and charged to 12 V. How much energy is stored in the capacitor? Use E = 8.85 × 10-12 F/m. Energy stored in a capacitor, E: ✓ J

A parallel-plate capacitor is made of two square plates 20 cm on a side and 1 mm apart. The capacitor is connected to a 50-V battery. Hint # a. What is the energy stored in the capacitor? Energy stored in the capacitor is b. With the battery still connected, the plates are pulled apart to a separation of 2 mm. What is the energy stored in the capacitor now? Energy now stored in the capacitor is c. This time, starting from situation in (a), with the batteries disconnected (but capacitors still charged), the plates are pulled apart to a separation of 2 mm. What is the energy stored in the capacitor now? Energy now stored in the capacitor is d. Comparing your results in (b) and (c) above, it makes sense that the energy stored in the capacitor- increases in (c), because the work done in separating the plates is stored as the electrostatic potential energy. In (b), why does the energy decrease even though work is done in separating the plates? E D Submit Question с 4 O The energy is not…

In (Figure 1), each capacitor has C= 5.00 μF and Vab = 35.0 V. Part A: Calculate the charge on capacitor C1. Q1=__C Part B: Calculate the potential difference across capacitor C1. V1=__V Part C: Calculate the charge on capacitor C2. Q2=__C Part D: Calculate the potential difference across capacitor C2. V2=__V Part E: Calculate the charge on capacitor C3. Q3=__C Part F: Calculate the potential difference across capacitor C3. V3=__V Part G: Calculate the charge on capacitor C4. Q4=__C Part H: Calculate the potential difference across capacitor C4. V4=__V Part I: Calculate the potential difference between points a and d. Vad=__V

The same voltage is applied between the plates of two different capacitors. When used with capacitor A, this voltage causes the capacitor to store 20 μC of charge and 5.8 x 10-5 J of energy. When used with capacitor B, which has a capacitance of 7.8 µF, this voltage causes the capacitor to store a charge that has a magnitude of qB. Determine qB. Number i Units