Consider a drug that is used to help prevent blood clots in certain patients. In dinical trials, among 6034 patients treated with this drug, 153 developed the adverse reaction of nausea. Use a 0.10 significance level to test the claim that 3% of users develop nausea. Does nausea appear to be problematic adverse reaction? Identify the null and alternative hypotheses for this test. Choose the correct answer below. OA Ho: p#0.03 H: p=0.03 OB. H: p=0.03 H:p<0.03 OC. Ho: p=0.03 H: p=0.03 OD. Ho: p=0.03 H:p>0.03 Identify the test statistic for this hypothesis test. The test statistic for this hypothesis test is (Round to two decimal places as needed.) Identify the P-value for this hypothesis test. The P-value for this hypothesis test is (Round to three decimal places as needed.)

Consider a drug that is used to help prevent blood clots in certain patients. In dinical trials, among 6034 patients treated with this drug, 153 developed the adverse reaction of nausea. Use a 0.10 significance level to test the claim that 3% of users develop nausea. Does nausea appear to be problematic adverse reaction? Identify the null and alternative hypotheses for this test. Choose the correct answer below. OA Ho: p#0.03 H: p=0.03 OB. H: p=0.03 H:p<0.03 OC. Ho: p=0.03 H: p=0.03 OD. Ho: p=0.03 H:p>0.03 Identify the test statistic for this hypothesis test. The test statistic for this hypothesis test is (Round to two decimal places as needed.) Identify the P-value for this hypothesis test. The P-value for this hypothesis test is (Round to three decimal places as needed.)

Name: Identify the conclusion for this hypothesis test.O A. Reject Ho - The
Uploaded: 2024-03-20T07:07:12.000Z
Channel: Bartleby
Description: Identify the conclusion for this hypothesis test.O A. Reject Ho - There is sufficient evidence to warrant rejection of the claim that 3% of users develop nausea.O B. Fail to reject Ho. There is sufficient evidence to warrant rejection of the claim t

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

Find the P-value that corresponds to the given standard score, and determine whether to reject the null hypothesis at the 0.05 significance level. Is the alternative hypothesis supported? z=3.5 for H₁: μ=124.5 kilograms and H₂: μ# 124.5 kilograms The P-value is (Round to four decimal places as needed.) Determine whether the alternative hypothesis is supported at a 0.05 significance level. O A. The P-value is more than the significance level. Do not reject Ho. The alternative hypothesis is not supported. OB. The P-value is more than the significance level. Reject Ho. The alternative hypothesis is supported. OC. The P-value is less than or equal to the significance level. Reject Ho. The alternative hypothesis is supported. O D. The P-value is less than or equal to the significance level. Do not reject Ho. The alternative hypothesis is not supported.
A health manager wants to assess the relationship between number of doctor visits and patient feedbacks.Patient feedbacks are categorized between 1= very bad and 5= very goodin a scale. The SPSS analysis is given below. Write down the hypothesis for this case and specify the test used and comment on the results. Patient Feedback Visit to Doctor 5.00 2.00 4.00 1.00 4.00 2.00 5.00 3.00 4.00 3.00 3.00 4.00 3.00 4.00 4.00 4.00 2.00 5.00 2.00 5.00 3.00 5.00 1.00 4.00 One-Sample Kolmogorov-Smirnov Test Kisisel Saglik Degerlendirmesi Gecen Yil Icindeki Hekim Ziyaret Sayisi N 12 12 Normal Parametersa,b Mean 3.3333 3.5000 Std. Deviation 1.23091 1.31426 Most Extreme Differences Absolute .206 .232 Positive .127 .127 Negative -.206 -.232 Kolmogorov-Smirnov Z .713 .802 Asymp. Sig. (2-tailed) .689 .541 a. Test…
Test the claim that the proportion of people who own cats is smaller than 60% at the 0.025 significance level. The null and alternative hypothesis would be: Ho: p=0.6 Ho:μ ≥ 0.6 Ho: p 0.6 The test is: left-tailed right-tailed two-tailed Based on a sample of 600 people, 53% owned cats The test statistic is: The p-value is: Based on this we: Ho:p>0.6 Ho: 0.6 Ho: μ 0.6 Reject the null hypothesis O Fail to reject the null hypothesis (to 2 decimals) (to 2 decimals) =
Find the value of the standard score, z, and determine whether to reject the null hypothesis at a 0.01 significance level. Is the alternative hypothesis supported? Ho p= 18.5 meters, H p18.5 meters, n= 144, x = 19.1 meters, o = 1.3 meters %3D The value of the standard score is (Round to two decimal places as needed.)
If the test requires that the results be statistically significant at a level of α = 0.05, fill in the blanks and complete the sentences that explain the test decision and conclusion. The decision is to reject the null hypothesis. There is enough evidence at a significance level of a = 0.05 that the mean weight for U.S. women of age 40-49 who smoke daily is less than 169.976 pounds.
Thanks
Using the results obtained for a study on website development below, how would we interpret the results of this hypothesis test? The claim is the percent of customers who abandon a web page due to long load times is different from 34%. The significance level is 0.10. The test statistic is 2.50. Select the correct answer below: Reject H0. There is strong evidence to conclude that the percent of customers who abandon a web page due to long load times is greater than 34%. Reject H0. There is NOT strong evidence to conclude that the percentage of customers who abandon a web page due to long load times is greater than 34%. Fail to reject H0. There is strong evidence to conclude that the percent of customers who abandon a web page due to long load times is greater than 34%. Fail to reject H0. There is NOT strong evidence to conclude that the percentage of customers who abandon a web page due to long load times is greater than 34%.
A health manager wants to assess the relationship between number of doctor visits and patient feedbacks.Patient feedbacks are categorized between 1= very bad and 5= very goodin a scale. The SPSS analysis is given below. Write down the hypothesis for this case and specify the test used and comment on the results. Patient Feedback Visit to Doctor 5.00 2.00 4.00 1.00 4.00 2.00 5.00 3.00 4.00 3.00 3.00 4.00 3.00 4.00 4.00 4.00 2.00 5.00 2.00 5.00 3.00 5.00 1.00 4.00 One-Sample Kolmogorov-Smirnov Test Kisisel Saglik Degerlendirmesi Gecen Yil Icindeki Hekim Ziyaret Sayisi N 12 12 Normal Parametersa,b Mean 3.3333 3.5000 Std. Deviation 1.23091 1.31426 Most Extreme Differences Absolute .206 .232 Positive .127 .127 Negative -.206 -.232 Kolmogorov-Smirnov Z .713 .802 Asymp. Sig. (2-tailed) .689 .541 a. Test…
In a study of the accuracy of fast food drive-through orders, one restaurant had 37 orders that were not accurate among 316 orders observed. Use a 0.01 significance level to test the claim that the rate of inaccurate orders is equal to 10%. Does the accuracy rate appear to be acceptable? Identify the null and alternative hypotheses for this test. Choose the correct answer below. OA. Ho: p=0.1 H₁: p=0.1 OB. Ho: p=0.1 H₁: p>0.1 ỌC. Hop=0.1 H₁: p<0.1 OD. Ho: p=0.1 k H₁: p=0.1 Identify the test statistic for this hypothesis test.
In a study of high school students at least 16 years of age, researchers obtained survey results summarized in the accompanying table. Use a 0.05 significance level to test the claim of independence between texting while driving and drivin when drinking alcohol. Are those two risky behaviors independent of each other? Click the icon to view the table of survey results. Determine the null and alternative hypotheses. Ho H₁: Determine the test statistic. x² = (Round to two decimal places as needed.) Determine the P-value of the test statistic. P-value = (Round to three decimal places as needed.) Do the results suggest that texting while driving and driving while drinking are related? Survey Results Texted While Driving No Texting While Driving Print 4 Drove When Drinking Alcohol? Yes No 740 158 Done 3058 4453 I X A. Reject the null hypothesis. There is sufficient evidence to warrant rejection of the claim that texting while driving happens 95% of the time when driving while drinking…
You are conducting a study to see if the probability of a true negative on a test for a certain cancer is significantly different from 0.27. You use a significance level of α=0.001. H0:p=0.27H0:p=0.27 H1:p≠0.27H1:p≠0.27You obtain a sample of size n=406n=406 in which there are 97 successes.What is the test statistic for this sample? (Report answer accurate to three decimal places.)test statistic = What is the p-value for this sample? (Report answer accurate to four decimal places.)p-value = The p-value is... less than (or equal to) αα greater than αα This test statistic leads to a decision to... reject the null accept the null fail to reject the null As such, the final conclusion is that... There is sufficient evidence to warrant rejection of the claim that the probability of a true negative on a test for a certain cancer is different from 0.27. There is not sufficient evidence to warrant rejection of the claim that the probability of a true negative on a test for a…
In the test of hypothesis H0:μ=100 vs . Ha:μ≠100, we already have the p-value for this test: P-value=0.025. Which of the following (with the reason) will be correct with significance level at .05? The information is not enough to make a decision. Reject H0 since the P-value is less than the significance level. Reject H0 since the P-value is greater than .01. Fail to reject H0 since the P-value is greater than .01. Fail to reject H0 since the P-value is less than the significance level.