Consider a circularly loaded flexible area acting on the ground surface. The radius of the circular area is 20 ft and the uniformly distributed load is q = 1,000 lb/ft2. Calculate the vertical stress increase, Δσz, at a depth of 10 ft for a radius of 0 ft (immediately below the center of the circular area) and 20 ft (immediately below the edge of the circular area).

Q: 4- Refer to Figure below. If H1=3 ft, H2=4.5 ft, h=1.5 ft, ysa=118.9 lb/ft³, area of the tank=6.25…

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Q: A clay stratum 8.0m thick is located at a depth of 6m from the ground surface. The natural moisture…

A: γsclay=G+e1+eγwwe knowSe=wGe=0.56×2.751=1.54so,γsclay=2.75+1.541+1.549.81=16.5688kNm3

Q: 2. The ground water level in a thick, very fine sand deposit is located 2.0 m below the ground…

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Q: a) determine the horizontal effective stress at A. (Ans. 53.36 kPa) b) determine the lateral…

A: For first layer,S = 30%Water Content (w) = 40%Specific Gravity of soil (GS) = 2.7For second…

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Q: Determine the total stress, effective stress, and pore water pressure at the depth of 9.5m for the…

A: Following is the given soil profile:   Also, Assuming the specific gravity of soil, G = 2.7

Q: 2. The ground water level in a thick, very fine sand deposit is located 2.0 m below the ground…

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Q: Problem 3.7 For the seepage situations shown in Figure, determine the effective normal stress on…

A: Solution1By considering pore water pressure::σ'=σ-uσ=20×2+3×9.81=69.43KPau=1+39.81=39.24σ'=30.2kpaBy…

Q: Calculate the effective stress at A. 25 m Sand and- Gravel Water Table Unit Weight (y) = 20.72 kN/m…

A: Following is the given soil profile:

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Q: C 6 m B A 5 m 3 m 6 m 3 m Fiq 23 - Prob 23

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Q: Question 2/ The soil profile shown in Figure (2) subjected to downward seepage calculate the…

A: Soil subdivision can be done in many ways and there are many types of soils such as clay, dust, etc.…

Q: SITUATION. From the soil profile shown below, Ground surface Dry Sand Clay A e = 0.49 Gs=2.68 Ground…

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Q: with a uniform pressure of 250 kPa. a) Calculate the vertical stress increase at points A (center),…

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Q: The water table is located at a depth of 3.0 m below the ground surface in a deposit of sand 11.0 m…

A: Given: The depth of the water table below the ground surface is 3 m. The thickness of the ground…

Q: 2m Dry zone Soil properties: Gs = 2.68 A e = 0.85 В 1.8 m Saturation zone (capillary rise) 0.9 m D…

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Q: 3 m 1 m A seepage flow condition is shown in the figure. The saturated unit weight of the soil Yar…

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Q: Question 1: (10) For the soil profile shown below where H1 = 5 m and H2 = 5 m: a) Calculate the…

A: Solution   in Dry Sandrd = G1+erw = 2.681+0.6x9.81rd = 16.431 kN/m3in ClayrSat = G+e1+e rw =…

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Q: Consider a circularly loaded flexible area on the ground surface. Given: radius of the circular…

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Q: a) Determine the effective stress at the bottom in kPa. b) Determine how high should the water table…

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Q: Q2/ Determine the variation of total and effective stresses and pore water pressure with depth for…

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A: Answer We know that horizontal total stress for at rest earth pressure is given by σH = Ko*σV σH =…

Q: show the variation beneath the edge of the loaded area.

A: Consider the following equation : σz=q1-11+r2232 Here r= 5ft Plot the variation of the vertical…

Q: Problem 5: A 3.5m thick silt layer underlain by a 3m thick clay layer is shown in Figure. Calculate…

A: In Siltr in between ABrb = G+Se1+erw = (2.7 +0)1+0.6 x 9.81r = 16.554 kN/m3r  in capillary layerrc =…

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Q: A soil profile is shown in Figure Q3(b)(i). The groundwater level is located on the ground surface.…

A: We are going to solve only three parts . for fourth part you have to re post this question. given…

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Q: 3. | Calculate the change in total vertical normal stress (o) and in effective stress (6') au a…

A: given data: water content, w = 35% = 0.35 Depth, h = 10 ft Degree of Stauration, S = 100% Specific…

Q: The saturated unit weight of a 10 m thick clay layer is 20 kN/m3. Calculate the vertical effective…

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Q: Plot the distribution of total stress, effective stress, and pore- water pressure with depth for the…

A: Following is the given soil profile:   Given: For soil up to the depth of 4.5 m (A-B): Void ratio,…

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A: Solution: The equation for determining the increase in stress on a flexible rectangular area at a…

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A: Q=500kN

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A: Clay strata: Water content=30%, Specific gravity=2.72 Sand strata: Water content=26%, Specific…

Q: A soil exists in an area where the ground surface is level and the groundwater table is 3 m below…

A: Given data: Lateral pressure,σh=0.5*vertical pressure, σv Saturated unit weight of soil, γs=22…

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Q: total effective stress acting at point A,

A: Given data: Unit weight of soil = 20.15 KN/m3 Specific gravity = 9.81 KN/m3

Q: SITUATION: In accordance with Boussinesq theory, the vertical stress at a point below the center of…

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Q: Calculate the effective stress at A. 25 m Sand and- Gravel Water Table Unit Weight (y) = 20.72 kN/m?…

A: Following is the given soil profile:

Q: The plan of a flexible rectangular loaded area is shown in Figure below. The uniformly distributed…

A:

Q: Calculate the effective stress at A. 25 m Sand and- Gravel Water Table Unit Weight (y) = 20.72 kN/m…

A: Given: The unit weight of water is 9.81 kN/m3. Consider the diagram,

Methods to Determine Vertical Stress

The load applied to the soil is transferred to the underground. The presence of water at soil pores and solid grains above the soil are the primary components that are responsible for the effective load transfer. Due to the load acting, the internal component of the soil or the underground formations undergoes deformations or a tectonic shift. The amount of deformation depends upon the amount of load acting on the soil surface, which indeed, depends on the weight of everything present above the soil. Due to this, the underground soil element develops internal stresses which try to resist the tectonic changes.