Consider a bi-convex lens with a diameter of 5 cm and zero thickness at its edges. A point object on the optical axis produces a real image on the opposite side. Both objects and images distances are 30 cm. The lens has a refractive index of 1.52. Using the equivalence of optical paths through the center and edge of the lens, determine the thickness of the lens at its center. 30 cm 30 ст 0.52 cm 0.45 cm O 0.34 cm 0.4 cm 0.5 cm O 0.31 cm

You have a thin, diverging lens. If the value of q (the distance from the image to the mirror along the principal axis of the mirror) is -3.57cm and the distance of p (the distance from the object to the mirror along the principal axis of the mirror) is 17.16cm, what is the focal length of the diverging lens? Object Ray 1 Principal focal point Virtual image Diverging lens Ray 1 Ray 3 Ray 2 Secondary focal point |fl ·|fl· Note: Do not explicitly include units in your answer (it is understood the unit is cm). Enter only a number. If you do enter a unit, your answer will be counted wrong.

A lens of focal length +24.0 cm is at x 0, and a second lens of focal length -24.0 cm is located at x = 16.0 cm. Let the positive x-direction be to the right. At what position x is the final image of an object that is 48.0 cm to the left of the positive lens? cm X = What is the magnification m of the image?.(Remember that magnification can be positive or negative.) m = The image is and virtual real Where should your eye be located and directed to see the image? O looking left from the right of both lenses looking left from between the lenses looking right from between the lenses O looking right from the left of both lenses Question Source: Freedman College Physic

On one side of a diverging lens of focal length 59.0 cm, you position an object of height 3.92 cm somewhere along the principal axis. The resultant image has a height of 2.74 cm. How far from the lens is the object located? 17.8 cm 25.4 cm 43.2 cm 33.0 cm