Consider a bar of length 5.5 m, being acted on by three forces and constrained to rotate about its left end. The magnitudes of the first two forces are 19 N and 26 N and the first force is acting on the end of the bar at an angle of 53 What is the torque in newton-meters, due to F1 on this bar relative to the left end?   What is the torque in newton-meters, due to F2 on this bar relative to the left end, if this force is acting at the midpoint of the bar? Use a coordinate system with positive directed out of the screen. What is the magnitude of the force F3, in newtons, if the force is a distance 0.25 m from the left end and the bar is not rotating?

axis is directed perpendicular to the plane of a square as shown in the figure. Two forces, F₁ and F2, are applied to diagonally opposite corners and act along the sides of the square, first as shown in part a and then as shown in part b of the figure. In each case the net torque produced by the forces is zero. The square is 1.00 m on a side, and the magnitude of F₂ is two times that of F₁. What are the distances a and b? F₁ t Axis F₂ O a=0.50 m, b = 0.50 m Oa=0.40 m, b = 0.50 m O a 0.20 m, b = 0.40 m a=0.40 m, b = 0.20 m a = 0.40 m, b = 0.40 m F₁ b (b) F₂

What are the torques for A, B and C? Note:use the given information

Suppose two long straight wires run perpendicular to one another without touching. Does one exert a net force on the other?If so, what is its direction? Does one exert a net torque on the other? If so, what is its direction? Justify your responses by using the right hand rules.

A circular-shaped object of mass 10 kg has an inner radius of 8 cm and an outer radius of 22 cm. Three forces (acting perpendicular to the axis of rotation) of magnitudes 13 N, 25 N, and 16 N act on the object, as shown. The force of magnitude 25 N acts 34◦ below the horizontal. Find the magnitude of the net torque onthe wheel about the axle through the centerof the object.Answer in units of N · m.

What is the torque produced by a force F = (-3î + 53)N being applied at * = (-2i – 2j)m ?

The answers are provided; please explain the purpose of each equation and why they were used Consider a bar of length 5.5 m, being acted on by three forces and constrained to rotate about its left end. The magnitudes of the first two forces are 19 N and 28 N and the first force is acting on the end of the bar at an angle of 43° What is the torque in newton-meters, due to F1 on this bar relative to the left end?   Ans. = 78.87 Nm Equation used: τ1 = rFsinθ   What is the torque in newton-meters, due to F2 on this bar relative to the left end, if this force is acting at the midpoint of the bar? Use a coordinate system with positive directed out of the screen. Ans. = 77 Nm Equation used: τ2 = F2 x (L / 2)   What is the magnitude of the force F3, in newtons, if the force is a distance 0.85 m from the left end and the bar is not rotating?  Ans. = 183.38 N  Equation used: F = (τ1 + τ2) / d

A wheel of inner radius r, = 13.4 cm and outer radius r, = 35.0 cm shown in the figure below is free to rotate about the axle through the origin O. What is the magnitude of the net torque on the wheel due to the three forces shown? (Assume F, = 3.80 N, F, = 6.60 N, and F = 14.6 N.) N. m 45.0 F,

A uniform rod is set up so that it can rotate about an axis at perpendicular to one of its ends. The length and mass of the rod are 0.769 m and 1.09 kg , respectively. A force of constant magnitude ? acts on the rod at the end opposite the rotation axis. The direction of the force is perpendicular to both the rod's length and the rotation axis. Calculate the value of ? that will accelerate the rod from rest to an angular speed of 6.03 rad/s in 8.01 s .

A bolt requires 272 Nm of torque to be unscrewed. If the maximum force you can apply is 232 N, what is the shortest wrench you can use to unscrew the bolt in cm?