
infoPractice Pack
infoPractice Pack
Confidence Interval for a Single Proportion
Example 2: Movie Goers are More Likely to Watch at Home
In a random sample of 500 movie goers in January 2013, 320 of them said they are more likely to wait and watch a new movie in the comfort of their own home. Find and interpret a 95% confidence interval for the proportion of movie goers who are more likely to watch a new movie from home.
Example 3:
(a) What is the margin of error for the confidence interval found in Example 2?
(b) What sample size is needed if we want a margin of error within ±2%? (Use the sample proportion from the original sample.)
(c) What sample size is needed if we want a margin of error within ±2%, and if we use the conservative estimate of p = 0.5?

Trending nowThis is a popular solution!
Learn your wayIncludes step-by-step video
Step by stepSolved in 2 steps with 3 images

- A Gallup poll of 1487 adults showed that 43% of the respondents have Facebook pages. Construct a 95% confidence interval for the proportion of adults who have a Facebook page.arrow_forwardA newspaper article stated that the US Supreme Court received 812 letters from around the country on the subject of whether to ban cameras from the courtroom. Of these 812 letters, 800 expressed the opinion that cameras should be banned. A statistics student was going to use this sample information to estimate a 95% confidence interval for the true proportion of all American adults feel that cameras should be banned from the courtroom. what is the 95% confidence interval?arrow_forwardIn a survey of 1000 households, 800 had cell phones but no landline. Construct a 95% confidence interval for the proportion of all households with a cell phone but no landline.arrow_forward
- 10arrow_forwardA research company is interested in determining the true proportion of Americans that work remotely. In a random sample of 200 individuals, 4.5% of them work remotely. Find a 90% confidence interval for the true proportion of Americans that work remotely.arrow_forwardIn a certain state, a survey of 500 workers showed that 38% belonged to a union. Find the 93% confidence interval for the overall proportion of workers who belong to a unionarrow_forward
- According to a poll, 81% of California adults (410 out of 506 surveyed) feel that education is one of the top issues facing California. We wish to construct a 90% confidence interval for the true proportion of California adults who feel that education is one of the top issues facing California.What is a point estimate for the true population proportion?arrow_forwardA sports news station wanted to know whether people who live in the North or the South are bigger sports fans. For its study, 121 randomly selected Southerners were surveyed and found to watch a mean of 4.6 hours of sports per week. In the North, 176 randomly selected people were surveyed and found to watch a mean of 3.2 hours of sports per week. Find a 90% confidence interval for the true difference between the mean numbers of hours of sports watched per week for the two regions if the South has a population standard deviation of 1.6 hours per week and the North has a population standard deviation of 1.4 hours per week. Let Population 1 be people who live in the South and Population 2 be people who live in the North. Round the endpoints of the interval to one decimal place, if necessary. Lower endpoint: Upper endpoint:arrow_forwardIn a survey of 1019 adults, a polling agency asked, "When you retire, do you think you will have enough money to live comfortably or not. Of the 10191 surveyed, 536 stated that they were worried about having enough money to live comfortably in retirement. Construct a 90% confidence interval for the proportion of adults who are worried about having enough money to live comfortably in retirement.arrow_forward
- a critic points out that this 95 % confidence interval is only accurate if the statistic follows a normal distrubution , or if the normal model is a good approximation. is this true for this data? explainarrow_forwardA poll showed that 40 out of 200 randomly chosen graduates of California medical schools last year intended to specialize in family practice. What is the width of a 95 percent confidence interval for the proportion that plan to specialize in family practice?arrow_forward
- MATLAB: An Introduction with ApplicationsStatisticsISBN:9781119256830Author:Amos GilatPublisher:John Wiley & Sons IncProbability and Statistics for Engineering and th...StatisticsISBN:9781305251809Author:Jay L. DevorePublisher:Cengage LearningStatistics for The Behavioral Sciences (MindTap C...StatisticsISBN:9781305504912Author:Frederick J Gravetter, Larry B. WallnauPublisher:Cengage Learning
- Elementary Statistics: Picturing the World (7th E...StatisticsISBN:9780134683416Author:Ron Larson, Betsy FarberPublisher:PEARSONThe Basic Practice of StatisticsStatisticsISBN:9781319042578Author:David S. Moore, William I. Notz, Michael A. FlignerPublisher:W. H. FreemanIntroduction to the Practice of StatisticsStatisticsISBN:9781319013387Author:David S. Moore, George P. McCabe, Bruce A. CraigPublisher:W. H. Freeman





