Compute the energy loss that would occur as 27 gal/min of water flows from a tank into a steel tube with an OD of 3.0 in and wall thickness of .025 in. The tube has a rounded inlet of radius (r) of .118 in.

Energy Equation: Example 2: h₂ 80 m = Datum D = 0.2 m 0.02)V² 2g L = 2000 m- = 0.02 V² D2g A horizontal pipe carries cooling water at 10°C for a thermal power plant. The head loss in the pipe is hL Q = 0.06 m³/s where L is the length of the pipe from the reservoir to the point in question, V is the mean velocity in the pipe, and D is the diameter of the pipe. If the pipe diameter is 20 cm and the rate of flow is 0.06 m³/s, what is the pressure in the pipe at L = 2000 m? Assume a₂ = 1.

Determine the kinetic energy correction coefficient for the compound channel shown in Figure 2.1 below. Im V,=0.5m/s V,=0.3m/s 20m 22m 3m Figure 2.1 4m V,=1.5m/s

Steam at a pressure of 0.08 bar and a quality of 99.0% enters a shell-and-tube heat exchanger where it condenses on the outside of tubes through which cooling water flows, exiting as saturated liquid at 0.08 bar. The mass flow rate of the condensing steam is 5.8 x 105 kg/h. Cooling water enters the tubes at 15°C and exits at 35°C with negligible change in pressure. Neglecting stray heat transfer and ignoring kinetic and potential energy effects, determine the mass flow rate of the cooling water, in kg/h, for steady-state operation. mwater = i 568765.92 kg/h