
Chemistry
10th Edition
ISBN: 9781305957404
Author: Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher: Cengage Learning
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Compound: CF3Cl
Valence electrons:
Bonds:
Lone pairs:
Electron geometry:
Molecular geometry:
Hybridization required:
polarity:
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- What is the hybridization of the highlighted atoms in the following structure? What are your estimates for the bond angles around these highlighted atoms? in what kind of orbital does the lone pair of electrons on the nitrogen reside?arrow_forwardSubstance: Cl4, I3-, SeF6 Lewis Structures # bonding groups # lone pairs # electron groups about the central atom Electron geometry Molecular geometry Bond angles Polarity # resonance structures Hybridization state about the central atomarrow_forwardIdentify hybridization and bond anglearrow_forward
- Answer the questions below about the highlighted atom in this Lewis structure: H - :0: || C-H In how many sigma bonds does the highlighted atom participate? In how many pi bonds does the highlighted atom participate? What is the orbital hybridization of the highlighted atom? Ú 0 X Śarrow_forwardGiven the molecule below, the bond angles marked x, y, and z are respectively. H H CHC 120°, 109°, 120° O90°, 180°, 109° H O 120°, 109, 109° O 120°, 109.5%, 180° CINTH Z (x), (y), and (z),arrow_forwardMolecule or Polyatomic HOCI NO₂ N₂H4 H₂O₂ Hint: the oxygens are connected (CH3)2NH Lewis structure H¬O—CI: | : 0=N–6: H-N-N-H H H H-0-0-H H H H-C-N -C-H .. HHH Hybrid- ization AXE 3 sp AX₂E2 2 sp² AX₂E 3 sp³ AX3E 3 sp AX₂E2 3 AX3E Electron pair geometry Molecular shape tetrahedral bent trigonal planar bent tetrahedral trigonal pyramidal tetrahedral bent tetrahedral trigonal pyramidal Bond angles ~109.5° ~109.5° all ~109.5° all ~109.5° all ~109.5° Bond Polarity Molecular Polarity if the molecule is polar, add a dipole arrow if not polar, state so and why H H H²O-OH Н H H" H H H Н Cl H 'H Harrow_forward
- Describe each highlighted bond in terms of the overlap of atomic orbitals. (If the highlighted bond is not a pi bond, select the blank option from the dropdown menu.) Compound 1: H H H-C-C-C-N: H -I H H Molecular orbital type: Atomic orbitals in the sigma bond: Atomic orbitals in the pi bond: Compound 2: H H CIH H-C-C-C H H CIH O H H Molecular orbital type: Atomic orbitals in the sigma bond: Atomic orbitals in the pi bond: H :N H C C ♥ C (> Carrow_forwardPlease help with number 10. ICI4-arrow_forwardPlease explainarrow_forward
- Give detailed Solution with explanation neededarrow_forwardComplete the following table: Lewis structure atoms: bonds between orbitals making each total bond order hybridization atoms: type E valence bond: between two atoms |Н: 1s C and H: o sp?(C) + 1s(H) C and H: 1 C: sp? Cl: sp3 0: sp? :0: || C and Cl: o sp?(C) + sp°(CI) C and Cl: 1 = sp?(C) + sp²(0) = p(C) + p(0) C and O: o C and O: 2 CI C and O: t C: C and C: C and C: C and C: C: H-C=C-H H: C and H: C and C: H: C and H: N: N and I: N and I: N= I: N and I: C: C and Cl: C and Cl: :Cl Cl: C and Cl: C and Cl: Cl: C and Cl: -c=cl: C and Cl: :Z: :U:arrow_forward
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