Compound B has molecular formula C9H12O. It shows five signals in the 1H-NMR spectrum - a doublet of integral 6 at 1.22 ppm, a septet of integral 1 at 2.86 ppm, a singlet of integral 1 at 5.34 ppm, a doublet of integral 2 at 6.70 ppm, and a doublet of integral 2 at 7.03 ppm. The 13C-NMR spectrum of B shows six unique signals (23.9, 34.0, 115.7, 128.7, 148.9, and 157.4). Identify B and explain your reasoning.

Draw the structure of the molecule with the following molecular formula, C3H¬CIO, and 'H NMR spectra (Chemical shift, multiplicity, #Hs): 2.0 ppm (quintet, 2H) 2.8 ppm (singlet, 1H) 3.7 ppm (triplet, 2H) 3.8 ppm (triplet, 2H)

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A compound with molecular formula C17H36 exhibits a 1H NMR spectrum with only one signal. How many signals would you expect in the 13C NMR spectrum of this compound? 3 3

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An unknown compound has the molecular formula C7H14O, and its 1H NMR and 13C NMR spectra are shown below. Determine the structure of the unknown compound and draw it below. Note that there are no peaks above 3 ppm in the 1H NMR, and the numbers present on the 1H NMR are the integration values for each set of peaks.

Compound A with the molecular formula of C12H15ClO₂ has the following ¹H-NMR spectral data: Chemical shift (ppm) 1.38 2.08 2.83 3.51 4.36 7.27 7.96 ¹H-NMR Spectrum Multiplicity triplet quintet triplet triplet quartet doublet doublet Integration Ratio 3 2 2 2 2 2 2 The IR spectrum of A exhibits a signal at 1738 cm-¹. Based on the above information, determine the structure of compound A with a detailed explanation.