Complete parts​ (a) and​ (b) below.   The number of dogs per household in a small town Dogs 0 1 2 3 4 5   Probability 0.629 0.227 0.093 0.027 0.015 0.010       ​(a) Find the​ mean, variance, and standard deviation of the probability distribution.   Find the mean of the probability distribution.   μ=nothing ​(Round to one decimal place as​ needed.) Find the variance of the probability distribution.   σ2=nothing ​(Round to one decimal place as​ needed.) Find the standard deviation of the probability distribution.   σ=nothing ​(Round to one decimal place as​ needed.) ​(b) Interpret the results in the context of the​ real-life situation.     A. A household on average has 0.6 dog with a standard deviation of 17 dogs.   B. A household on average has 1.0 dog with a standard deviation of 1.0 dog.   C. A household on average has 0.6 dog with a standard deviation of 1.0 dog.   D. A household on average has 1.0 dog with a standard deviation of 0.6 dog.

Q: Complete parts (a) and (b) below. The number of dogs per household in a small town Dogs 1 2 4…

A: Given,

Q: Calculate the mean, variance, and standard deviation of this probability distribution. (Show all…

A: Mean=E(X)=∑X P(X)          =(0 * 0.27)+(1 * 0.35)+(2 * 0.18)+(3 * 0.12)                +(4 *…

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Q: Complete parts (a) and (b) below. The number of dogs per household in a small town Dogs 0 2…

A: Given probability distribution table is,Dogs (X)Probability…

Q: (a) Find the mean, variance, and standard deviation of the probability distribution. Find the mean…

A: It is given as the probability distribution of the number of dogs per household in a small town.

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Q: Use the probability distribution to complete parts (a) and (b) below. The number of defects per 1000…

A: Defects012345Probability0.2580.2890.2430.1520.0380.020

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Q: Complete parts (a) and (b) below. The number of dogs per household in a small town Dogs 0 2…

A: From the provided information, The probability distribution table is as follow: Dogs 0 1 2 3 4 5…

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Q: Use the probability distribution to complete parts (a) and (b) below. The number of school-related…

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Q: Complete parts (a) and (b) below. The number of dogs per household in a small town Dogs 0. 1 3.…

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Q: Complete parts (a) and (b) below. The number of dogs per household in a small town Dogs Probability…

A:

Q: Complete parts (a) and (b) below. The number of dogs per household in a small town Dogs 0.…

A: a). The table shows the calculations for the mean: X p(X)p(X) X \cdot p(X)X⋅p(X) 0 0.653 0\cdot…

Q: Complete parts (a) and (b) below. The number of dogs per household in a small town Dogs 1 2 3 4…

A: Dogs(X) 0 1 2 3 4 5 P(x) 0.632 0.232 0.088 0.026 0.014 0.008

Q: Complete parts (a) through (c) below. The number of dogs per household in a small town Dogs 2…

A: Dogs Probability 0 0.621 1 0.239 2 0.093 3 0.026 4 0.014 5 0.006

Q: Use the probability distribution to complete parts (a) and (b) below. The number of school-related…

A: Solution Given data is

Q: The number of dogs per household in a small town Dogs 0 1 2 3 4 5   Probability 0.676 0.199 0.080…

A:

Q: Complete parts​ (a) and​ (b) below.The number of dogs per household in a small…

A: a.Find the average number of dogs per household in a small town using the given probability…

Q: Complete parts​ (a) and​ (b) below.   The number of dogs per household in a small town Dogs 0 1 2 3…

A:

Q: What is the variance of the random variable X?

A: It is given that the probability distribution for the random variable X.

Q: Use the probability distribution to complete parts (a) and (b) below. The number of school-related…

A:

Q: Complete parts (a) and (b) below. The number of dogs per household in a small town Dogs 3 4…

A:

Q: Complete parts​ (a) and​ (b) below.   The number of dogs per household in a small town Dogs 0 1 2 3…

A: a) The mean of the probability distribution can be obtained as:

Q: Complete parts (a) and (b) below. The number of dogs per household in a small town Dogs 1 3 4 5…

A: Let X be a random variable representing the number of dogs per household. Then, X has the PMF as:…

Q: Complete parts (a) and (b) below. The number of dogs per household in a small town Dogs Probability…

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Q: (a) Find the mean, variance, and standard deviation of the probability distribution.

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Q: Use the probability distribution to complete parts (a) and (b) below. The number of school-related…

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Q: Complete parts (a) and (b) below. The number of dogs per household in a small town Dogs 3 4…

A: Given probability distribution  Dogs 0 1 2 3 4 5 Probability  0.688 0.192 0.081 0.019 0.013…

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Q: Complete parts (a) and (b) below. The number of dogs per household in a small town Dogs 1 2 4…

A:

Q: Complete parts (a) and (b) below. The number of dogs per household in a small town Dogs 1 2 3 4…

A: Introduction: For a discrete random variable X, taking values X = x with probability mass function…

Q: Complete parts (a) and (b) below. The number of dogs per household in a small town Dogs 1 4…

A:

Q: The table below shoes the number of dogs per household in a neighborhood 0 1 2 3 4 5     0.686…

A: a).The expected value (mean) of the probability distribution can be obtained as follows:

Q: Use the probability distribution to complete parts (a) and (b) below. The number of school-related…

A: mean=E(X)=∑X.P(X)

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Q: Complete parts (a) and (b) below. The number of dogs per household in a small town Dogs 0 2…

A: we know that,mean(μ)=E(X)=∑X.P(X)E(X2)=∑X2.P(X)Variance(σ2)=E(X2)-(E(X))2standard…

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Q: Complete parts (a) and (b) below. The number of dogs per household in a small town Dogs 1 4…

A:

Q: Complete parts (a) and (b) below. The number of dogs per household in a small town Dogs 0 2…

A: Let X be the number of dogs having probability mass function is,  x 0 1 2 3 4 5 P(x)  0.638…

Q: Complete parts (a) and (b) below. The number of dogs per household in a small town Dogs 0 2…

A: x p(x) x*P(x) x2P(x) 0 0.663 0 0 1 0.214 0.214 0.214 2 0.083 0.166 0.332 3 0.02 0.06…

Q: Use the probability distribution to complete parts (a) and (b) below. The number of defects per 1000…

A: The number of defects and their corresponding probabilities are given.

Q: The number of defects per 1000 machine parts inspected Defects 1 2 4 5 Probability 0.262 0.295 0.236…

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Q: X 0 1 2 3 P(x) 0.2 0.1 0.1 0.6 Find the standard deviation of this probability distribution. Give…

A: We have given the Probability…